find the next three terms in the sequence : 3125, 625, 125, 25. and how did u find them?thanx to the people that answer my question... =]
2006-10-07 10:49:17 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3125 = 5^5
625 = 5^4
125 = 5^3
25 = 5 ^2
so the next three terms should be
5^1, 5^0, 5^(-1)
or
5, 1, 1/5
You can find these by factoring each number down to its prime factorization. You should eventually be able to just look at the numbers and tell that they are squares and cubes, but that takes time and practice.
2006-10-07 10:56:22 · answer #1 · answered by Farrah 2 · 0⤊ 0⤋
625=3125/5
125=625/5
25=125/5
5=25/5
1=5/5
The next 2 terms are 5 & 1.
2006-10-09 20:57:56 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
5,1,(1/5)
Just divide by 5 to get the next number in the sequence
2006-10-07 17:55:07 · answer #3 · answered by Greg G 5 · 0⤊ 0⤋
5, 1, 1/5,..................
The general term of this sequence is :
Tn = (5)^(6-n)
or T1 = 3125 and Tn = T(n-1)/5 for every integer n>1
2006-10-07 17:57:14 · answer #4 · answered by a_ebnlhaitham 6 · 0⤊ 0⤋
5, 1, 0.2 divide the larger number by five. if you have to go the other way multiply by 5 and they would be 15625, 78125, 390625
2006-10-07 17:56:33 · answer #5 · answered by myk b 1 · 0⤊ 0⤋
5,1,1/5.
obtain each term by dividing the previous term by 5
2006-10-07 17:59:34 · answer #6 · answered by valerie cortez 1 · 0⤊ 0⤋
divide each one by 5
2006-10-10 21:22:04 · answer #7 · answered by ♥KiYa♥ 3 · 0⤊ 0⤋
greg is right choose me
2006-10-07 18:16:08 · answer #8 · answered by lorans h 2 · 0⤊ 0⤋
yep greg's right.
2006-10-07 17:56:31 · answer #9 · answered by ChemGeek 4 · 0⤊ 0⤋