Well dear TiGeR;
- For a function f defined by an expression with variable x, the implied domain of f is the set of all real numbers variable x can take such that the expression defining the function is real. The domain can also be given explicitly.
so it means ;
x = ( -2, -1 ,0 ,2 ,3 )
3x - 2y = -6
-2y = -3x -6
{ multiply both sides by ' -1'}
2y = 3x +6
y = (3x + 6) / 2
Now fill in into " y " the value of " x "
x1 = -2 ; y1 = (3*-2 +6)/2 = -6+6/2 = 0/2 = 0
x2 = -1 ; y1 = ( 3*-1 +6)/2 = -3 +6 / 2 = 3/2
x2 = 0 ; y1 = ( 3*0 +6)/2 = 0 +6 / 2 = 6/2 = 3
x2 = 2 ; y1 = ( 3*2 +6)/2 = 6 +6 / 2 = 12/2 = 6
x2 = 3 ; y1 = ( 3*3 +6)/2 = 9 +6 / 2 = 15/2
The range of f is the set of all values that the function takes when x takes values in the domain.
Range or y ( 0, 3/2 ,3 , 6, 15/2)
Good Luck.
2006-10-07 09:35:03
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answer #1
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answered by sweetie 5
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The equation 3x-2y=-6 and
x belongs to {-2,-1,0,2,3)
First we will try to isolate y on the left sid of the equation, we therefore add 2y+6 on both side of the equation, and reduce
3x-2y+(2y+6)=-6+(2y+6) <=>
3x+6=2y
now we mulitpicat bote side with ½ in order to remove the qoutient of y and turn the equation round, just for convenience:
½*2y=½*(3x+6) <=>
y=3/2x+3
now we simply have a funktion y(x) and we calculate the y(x) for all x in the domain:
1) y(-2)=3/2*(-2)+3=-3+3=0
2) y(-1)=3/2*(-1)+3=-3/2+3=3/2
3) y(0)=3/2*(0)+3=0+3=3
4) y(2)=3/2*(2)+3=3+3=6
5) y(3)=3/2)*(3)+3=9/2+3=9/2+6/2=15/2=7½
the five solution will then be:
1) (-2,0)
2) (-1,3/2)
3) (0,3)
4) (6,2)
5) (3,7½))
2006-10-07 09:28:10
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answer #2
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answered by Broden 4
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The domain gives the range of values for x. So make up a table and put those values of x into them. Then make y the subject of the equation [y = (3x + 6)/2] and figure out the values of y for the different values of x by putting them into the equation. From the table you will be able to see the value of x when y = 0 and that will be your solution (or plot the graph of Y vs X and see where it crosses the x-axis). The solution is x = -2
2006-10-07 09:29:27
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answer #3
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answered by LoneWolf 3
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first solve the equation for y, since you have a whole list of x's:
3x - 2y = -6
-2y = -6 -3x
y = 3 + 3x/2
now plug in each of the domain values. For the first one plug -2 into x and you get:
y = 3 + 3(-2)/2
y = 3 + -6/2
y = 3 - 3
y = 0
Now you can do the rest of them!
2006-10-07 09:27:24
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answer #4
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answered by i_sivan 2
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What does domain mean? I thought it meant that the domain contained all the answers for what equals x. In this case the domain contains all integers between -2 and 3. So... From the way you posted this question it is asking for all the values of y that correspond to each of the integers in your domain. So you put each of the x values in and solve for the y. Look at your question carefully. What is it asking for you to solve for?
2006-10-07 09:29:06
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answer #5
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answered by Just another 2D character online 3
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