Use this formula:
log_b a = (log_c a) / (log_c b)
where c is any other base. Use whatever base your calculator provides, compute log 2 using that base, and divide by log 6 using that same base.
2006-10-07 07:33:03
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answer #1
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answered by James L 5
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first, u should know that the "log" on calculator generally stands for " log x(a positive real number) with base of 10".
so to get value of "log 2 based 6", just enter ("log"+2)/("log"+6).
2006-10-07 07:41:42
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answer #2
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answered by Dennis C 1
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Hi:
Try this: Log (2)/Log(6) =
this should give you the answer to the log(2) base 6
2006-10-07 17:43:28
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answer #3
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answered by Anonymous
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remember that:
LOGbase a (b) = LOG base c (b) / LOG base c (a)
So use the log base 10 or the log base e key on your calculator to compute log of 2 and log of 6 and divide them. Just use the same log key.
2006-10-07 07:36:29
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answer #4
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answered by holden 4
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Easy. Take log 2 and divide by log 6.
2006-10-07 07:35:07
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answer #5
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answered by animallover07 3
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3)9
2016-03-28 00:59:01
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answer #6
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answered by Anonymous
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Log base b of x is ln x / ln b.
Thus, Log base 10 of x is ln x/ln 10.
Thus: 2 [ln] [/] 6 [ln] [=]
Or use [log] in place of [ln].
2006-10-07 07:33:58
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answer #7
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answered by Anonymous
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Check the User's Manual that came with the calculutor. That will explain how to do it.
It depends on the calculator.
Good luck! :)
2006-10-07 14:42:31
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answer #8
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answered by Anonymous
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log(6)2 = (log(2))/(log(6))
2006-10-07 11:43:44
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answer #9
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answered by Sherman81 6
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Google "change of base rule" you might find something usefull.
2006-10-07 07:33:12
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answer #10
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answered by nitrojunkie78 4
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