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I need to enter Log 2 with a base of 6, how do I do this on a scientific calculator?

2006-10-07 07:31:04 · 11 answers · asked by Choad McChump 1 in Science & Mathematics Mathematics

11 answers

Use this formula:

log_b a = (log_c a) / (log_c b)

where c is any other base. Use whatever base your calculator provides, compute log 2 using that base, and divide by log 6 using that same base.

2006-10-07 07:33:03 · answer #1 · answered by James L 5 · 0 0

first, u should know that the "log" on calculator generally stands for " log x(a positive real number) with base of 10".


so to get value of "log 2 based 6", just enter ("log"+2)/("log"+6).

2006-10-07 07:41:42 · answer #2 · answered by Dennis C 1 · 0 0

Hi:

Try this: Log (2)/Log(6) =

this should give you the answer to the log(2) base 6

2006-10-07 17:43:28 · answer #3 · answered by Anonymous · 0 0

remember that:

LOGbase a (b) = LOG base c (b) / LOG base c (a)

So use the log base 10 or the log base e key on your calculator to compute log of 2 and log of 6 and divide them. Just use the same log key.

2006-10-07 07:36:29 · answer #4 · answered by holden 4 · 0 0

Easy. Take log 2 and divide by log 6.

2006-10-07 07:35:07 · answer #5 · answered by animallover07 3 · 0 0

3)9

2016-03-28 00:59:01 · answer #6 · answered by Anonymous · 0 0

Log base b of x is ln x / ln b.

Thus, Log base 10 of x is ln x/ln 10.

Thus: 2 [ln] [/] 6 [ln] [=]

Or use [log] in place of [ln].

2006-10-07 07:33:58 · answer #7 · answered by Anonymous · 0 0

Check the User's Manual that came with the calculutor. That will explain how to do it.

It depends on the calculator.

Good luck! :)

2006-10-07 14:42:31 · answer #8 · answered by Anonymous · 0 0

log(6)2 = (log(2))/(log(6))

2006-10-07 11:43:44 · answer #9 · answered by Sherman81 6 · 1 0

Google "change of base rule" you might find something usefull.

2006-10-07 07:33:12 · answer #10 · answered by nitrojunkie78 4 · 0 0

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