HELP ME PLEASE. I WAS JUST OFFERED A TRADE FOR ALONZO AND IT ALSO INCLUDED RIP HAMILITON.
2006-10-07 06:22:13 · 8 answers · asked by Anonymous in Sports ➔ Fantasy Sports
Alonzo and Rip for Ming, that's a big no.
Ming will score more points then those two combined,
Ming will have more rebounds then those two combined,
Ming will have a better FT% then those two.
Ming will have more blocks then those two combined.
You tell me if its fair.
Y. Ming
(Hou - C) FA 13 69 .519 .853 0 1271 581 85 30 94
R. Hamilton (is a ball hog)
(Det - SG) FA 58 86 .491 .845 55 1609 256 275 52 16
A. Mourning (is a back up)
(Mia - C) FA 133 97 .597 .594 0 509 359 11 13 173
Ming only played in 57 games last year due to injury's. If you do the math for 80 games Ming should have had
Ming should have had 1784 pts, 816 rbs, 120 ast, 40 steals, 136 blocks. Take his average of last year and *80.
Not to mention who would you have to cut to make the roster fit?
2006-10-07 06:34:37 · answer #1 · answered by Dan 3 · 0⤊ 2⤋
its noty abad trade
rip will get more touches this yoear with the full new offence they have in the D
Y M will get hurt like he always dose
and ao will put up soild #s
but kept him if you r one of those poeple that just want name peolpe personaly i like to have a soild team than 1 player that is medioker
2006-10-07 14:34:49 · answer #2 · answered by Anonymous · 3⤊ 0⤋
yao ming for alonzo and rip? hmmm....only if you are smoking crack you can. yao is better than alonzo, why need rip when you have tracy?
2006-10-07 13:26:27 · answer #3 · answered by Anonymous · 0⤊ 2⤋
no keep yao. HE is one of the amazing up and coming players
2006-10-07 15:30:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
No. For the love of God, no.
The person above me made it pretty clear. Good job!
2006-10-07 13:56:59 · answer #5 · answered by Adam C 4 · 0⤊ 2⤋
Are you serious? NO
2006-10-07 17:03:54 · answer #6 · answered by i_ball_4_lyf 2 · 0⤊ 0⤋
No, you'd be stupid to
2006-10-07 15:15:39 · answer #7 · answered by Greg 3 · 0⤊ 0⤋
NOPE.......
2006-10-07 13:24:24 · answer #8 · answered by Anonymous · 0⤊ 2⤋