2006-10-07 04:35:56 · 8 answers · asked by ocn64 1 in Science & Mathematics ➔ Mathematics
It's ten years, minus 11 days.
To see how many days are in the 10 years, start with 10*365=3650. Then add the number of leap days. There are two in this span, in 2000 and 2004.
Therefore, the total is 3650+2-11=3641.
2006-10-07 04:37:57 · answer #1 · answered by James L 5 · 0⤊ 0⤋
3640(PLEASE SEE THE EXPLAINATION BELOW)
1996=10+30+31=71
1997=365
1998=365
1999=365
2000=366
2001=365
2002=365
2003=365
2004=366
2005=365
(2006
=31+28+31+30+31+30+31+31+30+9
=282)
(SO NO. OF DAYS EXCLUSIVES OF 21 OCTOBER AND 10 OCTOBER)
=71+3287+282
=3640)
( WHAT ARE THE NO. OF DAYS BETWEEN TODAY AND THE DAY AFTER TOMORROW?IT IS 1 NOT TWO.)
2006-10-07 05:29:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
10/21/96-10/21-06 is 10 yrs=3650 days plus leap yrs in 2000 & 2004=3652.
10/10 is 11 days short of 10/21 so the answer is 3652-11=3641 days.
2006-10-07 06:36:36 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
something a Mulatto Socialist President does seems to be historic those days - this is all bearing directly to the flash and not the money. Wait till finally we could constantly pay for the movements of those Socialists in Washington.
2016-12-08 10:05:27 · answer #4 · answered by ? 4 · 0⤊ 0⤋
how much? in terms of price?
or do you mean
how MANY days...?
it is important to pose the question correctly to get a correct answer
number of days 3641
good luck
2006-10-07 04:49:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋
They cost you nearly ten years of your life.
2006-10-07 05:23:45 · answer #6 · answered by Jimbo 6 · 0⤊ 0⤋
alot, you have th get days in a year and take into account leap year too
2006-10-07 04:44:23 · answer #7 · answered by Jonathan 2 · 0⤊ 1⤋
3641 days
2006-10-07 04:45:29 · answer #8 · answered by raj 7 · 0⤊ 1⤋