find the dimensions of the rectangle.
Please be specific :)
2006-10-07 03:36:30 · 6 answers · asked by Jules 4 in Education & Reference ➔ Homework Help
L=2W+3, P=78
P=2L + 2W, P= 4W+6 + 2W
P=6W + 6
78 = 4W + 6 subtract 6 from both sides
72 = 6W divide by 6
12 = W
Width is 12, Length is 27
Good luck
2006-10-07 03:46:48 · answer #1 · answered by maddojo 6 · 0⤊ 0⤋
width of rectangle = w
length of rectangle = 2w + 3 (since it is 3 in. longer than twice width)
perimeter or rectangle is 2 x (length + width) = 78
perimeter of rectangle is 2 x (2w + 3 + w) = 78
therefore 4w + 6 + 2w = 78
which implies 6w + 6 = 78
which implies 6w = 78 - 6
which implies 6w = 72
which implies w = 72/6
therefore w = 12 in.
and length = 2w + 3 = 24 + 3 = 27 in.
2006-10-07 10:53:58 · answer #2 · answered by Einmann 4 · 0⤊ 0⤋
Length= 2W+3
width = 12
Length = 27
2006-10-07 10:40:08 · answer #3 · answered by jonn0boy 3 · 0⤊ 0⤋
2w+ 2(2w+3)=78 solve for w
2006-10-07 10:40:25 · answer #4 · answered by David B 6 · 1⤊ 0⤋
L=2W+3
2(L+W)=78
L+W=39
L-2W=3
subtracting
3W=36
W=12
L27
length=27 in
width=12 in
2006-10-07 10:39:23 · answer #5 · answered by raj 7 · 0⤊ 1⤋
do your own homework is that specific enough
2006-10-07 10:38:13 · answer #6 · answered by sleepwalker69 6 · 0⤊ 0⤋