area=(1/2)(b1+b2)*h
=(1/2)*18*5=45 sft
2006-10-07 03:34:58
·
answer #1
·
answered by raj 7
·
0⤊
0⤋
Area of trapezoid = ½ (sum of parallel bases) à height
= ½ (10 + 8) à 5
= 45 sq feet
So answer is b
2006-10-07 03:36:19
·
answer #2
·
answered by Lance 2
·
0⤊
0⤋
It's b. [(10+8)/2]*5=9*5=45!
2006-10-07 03:32:34
·
answer #3
·
answered by Nadia 1
·
0⤊
0⤋
Trapezpid Formula
A = 1/2h(b₁+ b₂)
A = 1/2(5)(10 + 8)
A = 1/2(5)(18)
A = 1/2(90)
A = 45 Square feet
- - - - - - - - - - - - - - - - - - - - - -
The answer is b (45 Sq feet)
2006-10-07 04:23:35
·
answer #4
·
answered by SAMUEL D 7
·
0⤊
0⤋
A=h(b1+b2)/2=5(10+8)/2=5*18/2=45
correct answer is b. 45
2006-10-10 15:12:54
·
answer #5
·
answered by yupchagee 7
·
0⤊
0⤋
Area = (h(a + c))/2
Area = (5(10 + 8))/2
Area = (5(18))/2
Area = 5(9)
Area = 45 ft^2
2006-10-07 04:19:14
·
answer #6
·
answered by Sherman81 6
·
0⤊
0⤋
That'd take a whole HEAP o' cipherin'!
2006-10-07 05:10:01
·
answer #7
·
answered by B0FF0 2
·
0⤊
0⤋
completely out of my depth
2006-10-07 03:28:53
·
answer #8
·
answered by sleepwalker69 6
·
0⤊
0⤋
Your teacher would know
2006-10-07 03:29:19
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
b
2006-10-07 03:29:45
·
answer #10
·
answered by s t 2
·
0⤊
0⤋