Thanks!
2006-10-07 01:59:44 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
okay let us see what we got here
(n^2-a^2) -(n-a)^2 = ?
now we take every part alone
which is
(n^2-a^2) = ( n+a ) ( n-a ) ---- difference square
(n-a)^2 = ( n-a) (n-a )
so it would be [( n+a ) ( n-a )]-[( n-a) (n-a )]
we take out the common divisor which is (n-a) here
so its gonna be
(n-a) [( n+a )-( n-a)]
( n+a )-( n-a) is a difference square method so it equal to n^2-a^2
so the answer is
(n-a)( n^2-a^2)
hope i eplained it well wishin you luck :)
2006-10-07 02:18:56 · answer #1 · answered by Anonymous · 2⤊ 1⤋
(n^2 - a^2) - (n - a)^2
((n - a)(n + a)) - ((n - a)(n - a))
(n - a)((n + a) - (n - a))
(n - a)(n + a - n + a)
(n - a)(2a)
ANS : (2a)(n - a)
2006-10-07 09:47:52 · answer #2 · answered by Sherman81 6 · 1⤊ 0⤋
(n^2-a^2) - (n-a)^2
= (n-a)(n+a) - (n-a)(n-a)
= (n-a) [2a]
Regards,
Mysstere
2006-10-07 09:02:25 · answer #3 · answered by mysstere 5 · 1⤊ 2⤋
(n^2-a^2)-(n-a)^2 = (n+a)(n-a)-(n-a)(n-a) = [(n+a)-(n-a)](n-a) =
= 2a(n-a)
2006-10-07 09:04:22 · answer #4 · answered by Eric Campos Bastos Guedes 3 · 1⤊ 2⤋
(n^2-a^2)-n^2-a^2
n^2-n^2-a^2-a^2
= -2a^2
2006-10-07 09:08:43 · answer #5 · answered by GeLo'14 3 · 0⤊ 4⤋
You give it a shot
2006-10-07 09:01:24 · answer #6 · answered by Anonymous · 0⤊ 3⤋
icer seems right
2006-10-07 09:18:12 · answer #7 · answered by Anonymous · 0⤊ 2⤋
2a (n-a)
2006-10-07 09:02:11 · answer #8 · answered by buccinator 3 · 1⤊ 1⤋