Factorise 2x^2 - 7x +6
2006-10-07 01:53:21 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^2 - 7x + 6 = 2x^2 - 3x - 4x + 6 = x(2x-3) - 2(2x-3) =
= (x-2)(2x-3)
2006-10-07 02:13:03 · answer #1 · answered by Eric Campos Bastos Guedes 3 · 1⤊ 1⤋
2*x^2-7x+6
(x-2 )(2x-3 )
check
x*2x-2*2x-3*x+(-2)(-3)
2x^2-4x-3x+6
2x^2-7x+6
2006-10-07 14:23:51 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
2x^2 - 7x + 6
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-(-7) ± sqrt((-7)^2 - 4(2)(6)))/(2(2))
x = (7 ± sqrt(49 - 48))/4
x = (7 ± 1)/4
x = (8/4) or (6/4)
x = 2 of (3/2)
ANS : (2x - 3)(x - 2)
2006-10-07 09:49:57 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
2x^2-7x+6
2x^2-x-6x+6
2x(x-1)-6(x-1)
= (2x-6)(x-1)
2006-10-07 09:25:39 · answer #4 · answered by Sean 3 · 0⤊ 0⤋
(2x-3)(x-2)
To check if answer is correct, use FOIL
(2x-3)(x-2) -----------------> 2x^2-4x-3x+6 = 2x^2-7x+6
2006-10-07 08:55:46 · answer #5 · answered by JSAM 5 · 0⤊ 0⤋
(2x-3)(x-2)
2006-10-07 10:49:19 · answer #6 · answered by smiley 1 · 0⤊ 0⤋
(2x-3)(x-2)
2006-10-07 08:56:31 · answer #7 · answered by buccinator 3 · 1⤊ 0⤋
its factoring 1st off
the answer is
(2x-3)(x-2)
2006-10-07 16:43:10 · answer #8 · answered by bRWnEyEdGiRL 2 · 0⤊ 0⤋