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Can someone form an inequality and find its solution for this problem??

There are 4 more boys than girls in a class of less than 52 students. How many boys are in the class? How many are girls?

Please, I need correct answers!
BIG THANKS to the ones who can give me the correct answer!!

2006-10-07 00:02:35 · 9 answers · asked by Camille May S 1 in Science & Mathematics Mathematics

9 answers

When they give you this answer of 27 boys and 23 girls = 50 which is of couse < 52 that is only one possible answer, other answers could be 26/22, 25/21, 24/20, 20/16, 19/15, 18/14. 17/13, 16/12, 15/11, 14/10, 13/9, 12/8, 11/7, 10/6, 9/5, 8/4, 7/3, 6/2 and 5/1. In each of these combinations the class is less than 52 and there are 4 more boys than girls.

2006-10-07 00:31:26 · answer #1 · answered by victorschool1 5 · 0 0

there are 24 girls and 28 boys and 52 students in all
if there are 50 students there are 23 girls and 27 boys
the formula is
b - 4 = g
g + b = 52
52 - 4 = 48
48 / 2 = 24(number of girls)
24 + 4 = 28(number of boys)

2006-10-10 13:56:30 · answer #2 · answered by ♥KiYa♥ 3 · 0 0

if there are to be less than 52 students and 4 more boys than girls we need the highets number below 52 divisible by 4 , which is 48
so there are totally 48 students in the class
if the girls are x in number than boys are x +4 in number
so answer is got by equation-- x+x+4= 48
the number of girls is 24 and boys are 24= 4 = 28
and total students are 24+28= 52

2006-10-07 00:11:52 · answer #3 · answered by girl 3 · 0 0

Let x= the number of girls, then x+4= the number of boys

x+x+4=52, 2x=52-4,2x=48, x=24

You have 24 girls, and 28 boys in the class.

2006-10-07 00:12:23 · answer #4 · answered by WC 7 · 0 0

This isn't an inequality (unless you thing having more boys than girls in the class is an inequality :)). It is a system of 2 equations & 2 unknowns:
b=g+4
b+g=52
g+4+g=52
2g=48
g=24
b=24+4=28
check
24+28=52

2006-10-07 07:03:48 · answer #5 · answered by yupchagee 7 · 0 0

Let

x = the number of girls

x + 4 = the number of boys

52 the total students

- - - - - - - - - - - - - - - - - - - - - - - - - - -

x + x + 4 = 52

2x + 4 = 52

2x + 4 - 4 = 52 - 4

2x = 48

2x/2 = 48/2

x = 24

The answer is x = 24

The solution set is { 24 }

Insert the x value into the equation

- - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Check

x + x + 4 = 52

24 + 24 + 4 = 52

24 + 28 = 52

52 = 52

- - - - - - - - - - - - - - - - - - - - - - - - - -

There are 24 Girls In class

There are 28 Boys In class

2006-10-07 02:49:44 · answer #6 · answered by SAMUEL D 7 · 0 0

i lll explain the whole system to yu

first lets assume ... let the boys be 'x' and girls be 'y'

so in the class total students will be 'x+y<52' as there are less than 52 students

now girls are 4 more than the boys so 'y+4=x'

now solve.

answer will be boys 28 and girls less than 24

simple enough ...

2006-10-07 00:10:57 · answer #7 · answered by Yash 3 · 0 0

x+(x+4)<52 x is the number of girls x+4 is number of boys
2x+4 <52
2x <48
x<24 and you can't have a fraction of a person

27 or less boys and 23 or less girls because it says there are less than 52 total.

2006-10-07 00:06:20 · answer #8 · answered by Me 3 · 0 0

let x= no. of boys
let y = no. of girls

x+y<52
where x=y+4

y+4+y<52
2y<48
y<24

x=24+4
x<28

there are at most 27 boys and at most 23 girls

2006-10-07 00:11:28 · answer #9 · answered by Croasis 3 · 0 0

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