Let f(x)=||2x-6| - |x+2||. The graph of f has corners when x is equal to A,B,C, and D. Assume A < B < C < D.

Question

Find A, B, C, and D.

Answer 1

The graph of |x| has a corner at x=0. Therefore, f(x) has a corner whenever ||2x-6|-|x+2||=0. This can happen when +/-(2x-6) = +/-(x+2), so there are four possibilities. Solve for x in each case, and you'll have A,B,C, and D.

Answer 2

i dont know how i can draw here.
its a continous function and graph has four corners as u said.
when x= -2 then f(x)= 10
when x= 4/3 then f(x)= 0
when x= 3 then f(x) = 5
when x= 8 then f(x)= 0

Answer 3

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