physics question below?

Question

The punter on a football team tries to kick a football so that it stays in the air for a long "hang time." If the ball is kicked with an initial velocity of 24.8 m/s at an angle of 61.5° above the ground, what is the "hang time"?

Answer 1

The time it hangs depends only on the vertical component of velocity vy = 24.8*sin(61.5º) m/s. It travels upward until gravity acceration reduces its velocity to zero, then downwards until it hits the ground. if the ground is level, the rise time will equal the fall time. The equation for the upward velocity is vy - at; the time to reach 0 is given by vy - a*t = 0, or t = vy/a. The hang time is twice this, or 2*vy/a. Put in vy from above to get the answer.