What is the maximum number of legal pitches one batter can take before recording an out, walk or hit? This includes balls and strikes, forget the foul balls.
2006-10-06
18:35:59
·
15 answers
·
asked by
Anonymous
in
Sports
➔ Baseball
I said to forget the foul balls
2006-10-06
18:55:27 ·
update #1
OK, we'll go with what idiot instructor said
"the maximum number of pitches (discounting any pitch which doesn't change the count) before another batter must come to the plate"
The answer isn't six or seven...
Good luck.
2006-10-06
20:12:09 ·
update #2
Mr HeeHaw, br549, is sniffing in the general proximity.
2006-10-07
02:29:10 ·
update #3
thorfin, if he gets hit, he loses his "at bat" HINT HINT
2006-10-07
07:41:19 ·
update #4
there isn't a limit on the number of pitches in an at bat.
2006-10-06 18:39:35
·
answer #1
·
answered by Michael L 5
·
0⤊
0⤋
The answer is 6 (four ball and 2 strikes (6) or 3 strikes and three balls (6) However, if there is a runner on base caught stealing, the batter at the plate starts over the next inning with a fresh count. But since they do not make the out, they could only have a maximum of 5 pitches. That could happen three times, if the batter came to bat with zero outs and the bases loaded in which case the number is 15 pitches.
So, since the batter never makes an out, the answer is 7 plus 7 plus 6 equals 20
2016-06-12 12:10:05
·
answer #2
·
answered by Mark 1
·
0⤊
0⤋
There is no maximum if you are going to require an out, walk or hit. Players can make numerous plate appearances without ever recording one of those options. If you mean the maximum number of pitches (discounting any pitch which doesn't change the count) before another batter must come to the plate, the answer is six. Five pitches to reach a full count, the sixth non-fouled off pitch must result in either an out or a base runner.
2006-10-06 19:01:37
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
in case you like an answer without foul balls, you will desire to assert that each and each batter gets a three-2 count huge form. additionally, you do no longer say suited activity, so one can say there are 3 walks (to load bases) and 3 strikeouts each inning. All take place after the batter gets a three-2 count huge form. Thats reminiscent of 6 pitches in line with batter cases 6 batters an inning cases 9 innings, which may be 324 pitches. With foul balls, you may get much extra, whether it is the optimum a glass can throw in a 9 inning shutout without a bad ball. Now granted, i think of the main I certainly have ever considered a glass throw in a activity develop into a hundred and forty pitches, so this could be a sprint far fetched.
2016-10-02 00:55:24
·
answer #4
·
answered by blumenkrantz 4
·
0⤊
0⤋
it's 6, 3 balls and 3 strikes, or else 4 balls and 2 strikes, the max number of pitches BEFORE an action is recorded is 5, either 3 balls and 2 strikes
2006-10-06 19:13:01
·
answer #5
·
answered by C_Millionaire 5
·
0⤊
0⤋
Wihtout the foul balls this question doesn't make any sense. The pitcher still gets the fouls added to his pitch count. If MLB counts them, then we have to as well. So, I say five (3 and 2 count) plus all the foul balls it would take to reach the curfew of a stadium or if they don't have one as many pitches as all the pitchers on the team could take before they got to sore to throw any more and had to forfiet them game
2006-10-07 00:57:50
·
answer #6
·
answered by Dan 4
·
0⤊
0⤋
It could be unlimited if he gets beaned everytime after reaching a full count.. because that sixth pitch is neither an out, a walk or a hit.. it's a hit by the pitch.. If he's lead off guy, and goes full count on five pitches, five times in one game and is hit by the pitch on the sixth throw.. he would have faced 30 pitches without recording an out, walk or hit.. and he would be oh-for-oh in the box score, but 5-for-5 in his on base percentage..
2006-10-07 03:04:28
·
answer #7
·
answered by thorfin39 3
·
0⤊
0⤋
100
2006-10-06 23:12:32
·
answer #8
·
answered by Vampire 2
·
0⤊
0⤋
since foul ball are consider strikes, you would have to multiply the number of bases loaded times the number of wooden bats in the dugout divide that by the number of empty seats in the 3rd section plus the number of vendors on the 2nd row minus the number of hotdogs in section 108 and times that by the length of a wicked slider and divide it by the width of a screwball...and I think the answer would be about 5.
2006-10-06 18:47:31
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
six to the n degree.... 4 balls and 2 strikes....next at bat same thing etc. makes the final out of a 23 year career...fourteen thousand plate appearances; one official at bat
2006-10-08 12:00:16
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋