The feldspars (feld ~'field', spar ~'rock') are a series of common
minerals based on aluminum and silicates. There are potassium forms, sodium forms, calcium forms, etc.
Some have been found to have exceptionally good properties as polishing compounds and have been marketed as powders for
cleaning and polishing.
There are other commercial applications as well.
2006-10-06 20:30:34
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answer #1
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answered by hls 6
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Feldspars are one of the most common minerals - they make up 60% of the earths crust and mainly form by crystallisation out of molten magma. They are found in a wide range of rocks, through the igneous-rock spectrum, in some metamorphic rocks (rocks formed by re-heating and re-pressurisation of other rocks), and are recycled in to many sedimentary rocks.
They are an aluminium-silicate mineral, made of interlocking tetrahedrons of SiO4 and AlO4. A general formula is X Al(1-2) Si(3-2) O8, where X is sodium and/or potassium and/or calcium. There is a gradation between K, Na, and Ca end-member forms of the mineral, and 9 common feldspar minerals are separated.
The K end-member feldspars have a slightly different structure and, by eye, people will often just separate orthoclase (K-feldspar) and plagioclase (the rest) feldspars. K-feldspars are more common in felsic igneous rocks (like granite). Sometimes they have a pinkey tinge.
Feldspars are less resistant to weathering than, for example quartz, and over time decay away to form clays.
2006-10-07 08:57:34
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answer #2
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answered by Anonymous
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Feldspars is a group of minerals which have the same characteristics.
2006-10-10 13:21:30
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answer #3
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answered by greylady 6
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Feldspar is one of the component minerals found in Granite...
2006-10-07 01:06:51
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answer #4
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answered by Anonymous
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feldspar is a very common mineral. it is often pink/orange in color.
2006-10-07 06:18:38
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answer #5
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answered by Brooks B 3
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feldspars or felspars are a groups of aluminosilicates .they use to make enamels.
2006-10-07 04:08:35
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answer #6
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answered by ferry 2
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Tlhe simple answer is rock.
2006-10-08 00:44:50
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answer #7
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answered by kriend 7
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