I have answered "a" questions so far. "B" of those were awarded "best answer". I need "n" consecutive best answers in addition to my total answers in order to acheive "d" as a best answer percentage. What algebraic equation would I write to determine what "n" is?
2006-10-06 15:56:34 · 3 answers · asked by Bob 3 in Science & Mathematics ➔ Mathematics
d=100*(B+n)/(a+n)
If you have n consecutive best answers starting now, then at the end you will have B+n best answers, and a+n total answers.
Divide the number of best answers by the total number of answers and multiply by 100 to get the percent.
Solving for "n", we get
n=(100xB - axd)/(d - 100)
2006-10-06 16:10:34 · answer #1 · answered by DadOnline 6 · 1⤊ 0⤋
Start with the rational equation (B+n)/((a+n) = d.
This means that B (your best answers so far) and n (your needed best answers) are added and divided by the total of all answers both given and hypothetical. Then solve for n. This gives you n=(da-B)/(1-d).
This assumes your percentage is written as a decimal and not as a whole number. If it is a whole number, divide by 100 before plugging in.
2006-10-06 23:08:40 · answer #2 · answered by qamlof 2 · 0⤊ 0⤋
d/100= (B+n)/(a+n)
2006-10-06 23:07:19 · answer #3 · answered by Greg G 5 · 0⤊ 0⤋