I am having a ton of trouble with this one question on my algebra homework. It's driving me insane! I've been on it for at least 30 minutes, but still don't get it. Can anyone help me?
I'm supposed to simplify it...
6[v + (9w)] + (5)(3v-w)
Thanks in advance!
2006-10-06 15:08:05 · 8 answers · asked by revl92 2 in Education & Reference ➔ Homework Help
I feel like a complete dufus.
The problem is -6[v + (-9w)] + (-5)(3v-w)
2006-10-06 15:16:29 · update #1
Have you learned the rule of PEMDAS?
Parantheses
Exponents
Multiplication
Division
Addition
Subtraction
Now, what you do is work with what is in the Parantheses first.
-6[v + (-9w)] + (-5)(3v-w)
v-9w are not like terms, so you must leave them that way.
Same with 3v-w.
There are no Exponents, but here you must Multiply -6 with v-9w, which would be -6v+54w.
-6v+54w+(-5)(3v-w)
Now, you must Multiply -5 with 3v-w, which would be -15v+5w.
Now you're left with -6v+54w-15v+5w.
There is no need to deal with Division, but you have to do Addition and Subtraction with like terms.
So, -6v-15v=-21v, while 54w+5w=59w.
The answer is -21v+59w.
If you had a problem with the brackets, don't worry, they're just like parantheses, except you deal with them after the normal parantheses.
If you had a problem with the negatives and positives, remember that Positive x Positive=Positive, Negative x Positive=Negative, and Negative x Negative=Positive.
And that's how I always simplify a problem.
2006-10-06 15:27:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
6[v+(9w)] +(5)(3v-w)
OK,
You know that 9w means 9 times w right? just making sure.
Also remember order of operations - you always do the parenthesis first, then multiply or divide whetever needs to be, THEN you add or subtract.
Distribute the 6 in the first part. You have v times 6 and 9w times 6
6 x v + (6 x 9 x w)
multiply 6 x 9 = 54
So the first part is 6v+54w
and the same for the 5. Multiply 3v times 5 and the -w by 5
(5 x 3v) - (5 x w)
5 x 3 = 15
So
15v-5w
Now add the two parts
6v+54w + 15v-5w=
(6v + 15v) + (54w-5w)=
21v+ 49w
2006-10-06 15:23:06 · answer #2 · answered by scientista 1 · 0⤊ 0⤋
This is really not a hard problem - you're just having a bad day.
Remove the parenthesis around 9w:
6[v + (9w)] + (5)(3v - w)
6[v + 9w] + (5)(3v - w)
Remove the parenthesis around 5:
6[v + 9w] + 5(3v - w)
Now, use the distributive property to multiply 6 across the brackets:
6v + 54w + 5(3v - w)
Do the same for the 5(3v - w):
6v + 54w + 15v - 5w
Combine like terms:
6v + 54w + 15v - 5w
(6v + 15v) + (54w - 5w)
21v + 49w <== Simplified
---------------------
Please note that this is *simplified*
- (not solved for "v" or "w" as stated by the second answerer).
You're welcome to e-mail me if you need additional help or clarification.
Good luck in your classes.
2006-10-06 15:11:37 · answer #3 · answered by Mitch 7 · 1⤊ 1⤋
first u take the left side i.e.,6.multiply the number with numberrs inside the bracket.then the same.then u will same variables that is v and w .if there is + u add the like variables or if u have - variable u are supposed to subtract the number.
6v+54w+15v-5w
=21v+49w
2006-10-06 15:16:23 · answer #4 · answered by lock 2 · 0⤊ 1⤋
If you're in Australia, sort within the first four digits of your cellphone quantity at step a million. Then it really works. It's a functional calculation made tricky: X - first part of your cellphone quantity Y - moment part of your cellphone quantity X*(eighty+a million)*250=X*20250 X*20250+two*Y=two*(X*10,000+Y)+250 now subtract 250 and divide by way of two leaves you with X*10,000+Y that is your cellphone quantity To get the primary part of your cellphone quantity to 'become a member of up' with the moment side you have got to multiply it by way of 10,000 (shift it four decimal locations to the left). Clever although...
2016-08-29 06:45:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋
im not sure if its right but it may be?
6[v+(9w)]+(5)(3v-w)
v+3v=4v
6[4v+(9w)]+(5)(-w)
9w+w 10w
6[4v+10w]+(5)
Sorry if its wrong im only on 9th grade but we are just learning how to do these kinds of problems and it might actually be right- sorry though if its wrong.
2006-10-06 15:24:19 · answer #6 · answered by Bridgette ♥ 5 · 0⤊ 1⤋
I would go ahead and multiply to
6v + 54w = 15v - 5w
move like variables to 1 side:
59w = 9v
w = 9/59 v
2006-10-06 15:12:20 · answer #7 · answered by want2no 5 · 0⤊ 3⤋
use this as a guide
please excuse my dear aunt sally
1. p is for ( )
2. e is for exponents
3. m is for multiply
4. d is for division
5. a is for addition
6. s is for subtraction
do these steps in order
hope this helps!!!!!!!
2006-10-06 15:22:23 · answer #8 · answered by angelwings 2 · 1⤊ 0⤋