Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.
2006-10-06 13:00:00 · 5 answers · asked by Ash1227 2 in Science & Mathematics ➔ Mathematics
The slope of the given line is -3.
The negative reciprocal of -3 is 1/3
Use the formula y = mx + b, where m is the slope and b is the y-intercept.
m = 1/3 and b = 5
Answer: y = (1/3)x + 5
2006-10-06 13:01:20 · answer #1 · answered by MsMath 7 · 2⤊ 0⤋
Line A and line B are perpendicular if the product of their slope is -1. It will happen only if the slope of line B is negative reciprocal of the slope of line A.
Line A: y = –3x + 1
*line is in the form y=mx+b where m is the slope and b is the y-intercept.
Therefore the slope of line A is -3
The slope of line b would be 1/3
-3(1/3)=-1
The y-intercept is 5 from (0,5)
................................................
Line B:
m=1/3
b=5
Substitute this values in the equation y=mx+b
y=x/3+5
This can be your answer or you can put it in the standard form a line.
3y=x+15
x-3y+15=0
2006-10-06 21:37:35 · answer #2 · answered by Lin 2 · 0⤊ 0⤋
We will use the slope intercept form since we already have the intercept & can get the slope very easily.
y=mx+b where b=5
the slope of a perpendicular line is -3 so the slope of the line is it's negative reciprical or 1/3 so:
y=(1/3)x+5
2006-10-06 22:07:27 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
y=(1/3)x+5
2006-10-07 16:54:50 · answer #4 · answered by bRWnEyEdGiRL 2 · 0⤊ 0⤋
y - y1 = m (x - x1) (0,5)
Perpendicular slope m = -3
m = 1/3 reciprocal for perpendicular slope
y - 5 = 1/3 (x - 0)
y = 1/3x + 5
Graph original problem to find the line in question.
Good Luck
2006-10-06 20:08:24 · answer #5 · answered by fenx 5 · 0⤊ 0⤋
damn that mathgirl is fast
y = x/3 + 5
2006-10-06 20:08:23 · answer #6 · answered by Orinoco 7 · 0⤊ 0⤋