2006-10-06 11:38:35 · 16 answers · asked by Carlyn 2 in Science & Mathematics ➔ Mathematics
to solve you need to place 2 in for any m in the equation so you get
(2)(2)-2(2) and then you multiply
4-4 and then subtract
0
2006-10-06 13:56:43 · answer #1 · answered by ginaween 2 · 0⤊ 0⤋
if m = 2 then (2)(2)-4 so its 0
2006-10-06 18:46:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If m = 2, then plug 2 into each time you see an m, then simplify to solve.
So for this example, you get (2)(2) - 2*2 = 4 - 4 = 0
So 0 is your answer.
2006-10-06 18:41:17 · answer #3 · answered by pecosbill2000 3 · 0⤊ 0⤋
Common...
0
2006-10-06 19:48:08 · answer #4 · answered by Adriana 5 · 0⤊ 0⤋
Substituting 2 for m gives you (2)(2)-2*2=4-4=0.
2006-10-06 18:41:18 · answer #5 · answered by James L 5 · 0⤊ 0⤋
4-4= 0.
2006-10-06 19:42:18 · answer #6 · answered by steiner1745 7 · 0⤊ 0⤋
putting the value of m in equation we get:
(2)(2)-2(2)=4-4=0
hence ur answer is zero
2006-10-07 13:37:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Zero
2006-10-06 18:46:36 · answer #8 · answered by joy b 2 · 0⤊ 0⤋
Zero
2006-10-06 18:46:16 · answer #9 · answered by freedomchild99 3 · 0⤊ 0⤋
(m)(m)-2m=m^2-2m
m=2
2^2-2*2=4-4=0
2006-10-09 20:24:31 · answer #10 · answered by yupchagee 7 · 0⤊ 0⤋