Rose colour, or any other flower's colour for that matter, is determined primarily by the production of pigments, usually anthocyanins or carotenoids, but the shade and intensity of the colour are often changed by other factors such as vacuolar compounds, pH and metal ions. Pigmentation can also be affected by the shape of epidermal cells, especially those facing prospective pollinators. A conical shape is believed to increase the proportion of incident light that enters the epidermal cells, enhancing light absorption by the floral pigments, and thus the intensity of their colour.
2006-10-06 14:14:59
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answer #1
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answered by Natasha 2
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Roses come in many colors, from red to pink to white. Don't know if they have blue or purple ones yet.
In any case, you see a plant is a particular color because of how light is absorbed in that plant. Roses appear red because all the other colors in the spectrum are absorbed by the cells of the petals, but the red color is reflected back, which you perceive as red. This is why leaves appear green for the most part, all the wavelengths of light are absorbed but for green which is relfected back.
2006-10-06 18:05:59
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answer #2
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answered by phantomlimb7 6
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The various colors of roses have to do with the light spectrum reflected from the particular cellular make-up of the flower.
2006-10-06 18:02:40
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answer #3
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answered by Joe Cool 6
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differnt types of roses are different colours. Red is just the most popular
2006-10-06 19:59:33
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answer #4
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answered by starla_o0 4
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Many aren't. Some are pink, white, yellow, orange, gold, blackish, etc. They are genetically engineered for their specific colors and aromas.
2006-10-06 18:01:10
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answer #5
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answered by robert r 5
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They are red becuase they reflect red light and absorb the other lights.
2006-10-06 18:00:21
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answer #6
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answered by t_nguyen62791 3
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Or pink, blue, yellow etc
2006-10-06 18:00:55
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answer #7
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answered by rabbit_gate 1
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hmmm y u born ??
2006-10-06 18:04:32
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answer #8
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answered by LOST 6
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and yellow and orange and white.........
2006-10-06 18:00:37
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answer #9
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answered by Anonymous
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