Let's say I have this equation:
-2x^3 + 3x^2*((3x^2)^1/2)-5 = 0
How do I solve this using the TI-84 calculator?
If not can you show me how to do this without using the calculator?
2006-10-06 09:41:28 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You enter that (-2x^3 + 3x^2*((3x^2)^1/2)-5) into the Equation Solver (MATH > 0. Solver)..
Then press ALPHA+SOLVE and you'll see that
x=-.9312713733... and 1.1586947142...
FYI, you'll need two different guesses to get both answers, try -1 and 1 and you'll see both answers...
Check out the searchable TI 84 GuideBook at http://education.ti.com/educationportal/sites/US/productDetail/us_ti84pse.html?bid=6 for future reference...
2006-10-08 10:00:07 · answer #1 · answered by Em 5 · 3⤊ 0⤋
First, note that (3x^2)^1/2 is the square root of 3x^2, and equal to (sqrt 3) * x.
Therefore, 3x^2*((3x^2)^1/2) is the same as 3 x^2 (sqrt 3) x, which simplifies to (3 sqrt 3) x^3.
Your equation becomes
-2 x^3 + (3 sqrt 3) x^3 - 5 = 0
Add like terms and move the 5 to the other side:
(3 sqrt 3 - 2) x^3 = 5
Divide:
x^3 = 5 / (3 sqrt 3 - 2)
You can now take the third power root,
x = {5 / (3 sqrt 3 - 2)}^(1/3)
or approximately 1.1609.
2006-10-06 10:30:01 · answer #2 · answered by dutch_prof 4 · 0⤊ 1⤋
Multiply each and every thing by using x... that provides you with a quadratic -9x + x^2 = -18 x^2 - 9x + 18 = 0 (x - 6)(x - 3) = 0 x - 6 = 0 or x -3 = 0 x = 6 or x = 3 examine: -9 + 3 = -18/3? yep -9 + 6 = -18 / 6? yep
2016-11-26 21:39:06 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Sorry I cant show you how to do it on the calculator.
However, I can solve it over here.
-2x^3 + 3x^2*((3x^2)^1/2)-5 = 0
-2x^3 + 3x^2*Sqrt(3)x = 5
x^3(3sqrt3 - 2) = 5
x^3 = 5 / (3sqrt3 - 2)
x^3 = 5 / 3.1962
x^3 = 1.564
x = 1.161
2006-10-06 11:21:17 · answer #4 · answered by aazib_1 3 · 0⤊ 1⤋
-2x^3 + 3x^2*((3x^2)^1/2) = 5
-2x^3 + 3^1.5x^3 = 5
x^3 (3xsqrt(3) - 2) = 5
x^3 = 5/(3 x sqrt(3) - 2)
x = (5/(3 x sqrt(3) - 2))^1/3
I don't have a calculator with me...
2006-10-06 09:47:32 · answer #5 · answered by buaya123 3 · 1⤊ 1⤋
you can insert the left side of that equation into y1=
then put y2=0 for the second equation
Then look on the graph for the intersection points and find those points by using the Intersect function on the calculator
2006-10-06 09:46:45 · answer #6 · answered by Greg G 5 · 0⤊ 1⤋
-2x^3 + 3x^2(3x^2)^(1/2) - 5 = 0
x^3(3sqrt(3)-2) = 5
x = (5/(3sqrt(3)-2))^(1/3)
keystrokes:
3, √x, *, 3, - 2, =, /, 5, 1/x, x^y, (, 1, /, 3, ), =
(dunno if the TI-84 has INV and x^3 keys, pretty sure it will have a √x key)
2006-10-06 09:58:07 · answer #7 · answered by Helmut 7 · 0⤊ 1⤋