Suppose while playing ball?

Question

that a catcher gives with the ball when he catches a 0.113 kg baseball that is moving at
21.9 m/s. If he moves his glove 7.24 cm, what is the average force acting on his hand?? answer in kN.

Repeat where the glove and the hand move 10.1 cm, but answer in N.

Still trying to figure this one.......

Answer 1

First, work the deceleration with
v^2 = u^2 + 2as
0^2 = 21.9^2 + (2 x a x 0.0724)
0 = 479.61 + 0.1448a
-479.61 = 0.1448a
a = -3312.22 m/s^2

Now, F = ma = 0.113 x -3312.22 = -374.28N = -0.374kN

Do the other one yourself. OK?

Answer 2

First you need to calculate time t
s = 0.0724 m, u = 21.9 m/s, v=0

v² - u² = 2as
- 479.61 = 2 × a × 0.0724
a = - 3312.22 m/s²

v = u + at
v = 21.9 - 3312.22 × t
t = 0.007 sec

so impulse = av force × time
mv - mu = F(av) × t
F(av) = 0.113( - 21.9) / 0.007
= 353.52 N
= 0.3535 kN

Answer 3

kinetic energy = work = force * distance