f(-4)=
2006-10-06 08:58:17 · 13 answers · asked by lilb 1 in Science & Mathematics ➔ Mathematics
When you are finding f(value), it just means you plug the value into the function and solve.
f(x) = 3x^2 + 9
f(-4) = 3(-4)^2 + 9
f(-4) = 3(16) + 9
f(-4) = 48 + 9
f(-4) = 57
2006-10-06 09:17:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
f(x)=3x^2+9
f(-4)=3(-4)^2+9
=3(16)+9
=48+9
=57
2006-10-10 03:15:35 · answer #2 · answered by srirad 2 · 0⤊ 0⤋
57
2006-10-06 08:59:25 · answer #3 · answered by buccinator 3 · 0⤊ 0⤋
57
2006-10-06 09:00:01 · answer #4 · answered by Anonymous · 0⤊ 1⤋
f(-4)=3(-4)^2+9=3*16+9=48+9=57.
2006-10-06 08:59:24 · answer #5 · answered by James L 5 · 1⤊ 0⤋
for f(x)=....
x=-4 f(-4)=3*(-4)2+9=57
2006-10-06 09:31:02 · answer #6 · answered by Majdi B 3 · 0⤊ 0⤋
57
Why?
Set x=-4
x^2=(-4)*(-4)=16
3x^2=3*16=48
3x^2+9=48+9=57
2006-10-06 09:00:07 · answer #7 · answered by Stuart T 3 · 0⤊ 0⤋
f(x) = 3x^2 + 9
replacing x = -4 we get,
f(-4) = 3(-4)^2 + 9
f(-4) = 3*16 + 9
f(-4) = 48 + 9
f(-4) = 57
2006-10-06 09:02:02 · answer #8 · answered by aazib_1 3 · 0⤊ 0⤋
201 I think. Oh, my bad, I was thinking it was -4 cubed. Yeah, 57.
2006-10-06 09:00:37 · answer #9 · answered by Anonymous · 0⤊ 0⤋
f(x)=3x^2+9
f(-4)=3(-4)^2+9
f(-4)=3*16+9
f(-4)=48+9=57
2006-10-06 10:08:24 · answer #10 · answered by yupchagee 7 · 0⤊ 0⤋