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What is the slope of line A (5,4) and B (0,3) ??

thank u very much

2006-10-06 03:53:38 · 11 answers · asked by Laugh-n-fart 3 in Science & Mathematics Mathematics

11 answers

Slope of a line

Slope = Vertical Change / Horizontal change

Slope Formula

m = y₂- y₁/x₂- x₁

Ordered Pair

(5, 4)(0, 3)

m = 4 - 3/ 5 - 0

m = 1/5

The answer is m = 1/5

The solutio set is { 1/5 }

2006-10-06 04:06:03 · answer #1 · answered by SAMUEL D 7 · 0 0

slope=m=rise/run
4+3/5+0
8/5 Ans or slope of the given line

2006-10-06 12:10:27 · answer #2 · answered by Anonymous · 0 0

4

2006-10-06 10:54:38 · answer #3 · answered by j_son_06 5 · 0 2

the equation of a straight line is y=mx+c, where m is the slope. c is the intercept.
m is = y1-y2/x1-x2 sine it is the two points on the line that is given. here it is 4-3/5=1/5=0.2

2006-10-06 13:48:26 · answer #4 · answered by Mathew C 5 · 0 0

m = (Y2-Y1) / (X2-X1)
pick which point is 1 & 2
a=1 (5,4) b=2 (0,3) so ...(3-4) / (0-5) = -1 / -5 = 1/5

a=2 b=1 (4-3) / (5 - 0) = 1/5

2006-10-06 10:59:26 · answer #5 · answered by Brian D 5 · 0 0

Slope is (y2-y1) / (x2-y1) (Rise over run as someone else noted)


That gives (3-4) / (0-5)

Which yields -1/-5 or

1/5 as your slope.

Regards,

Mysstere

2006-10-06 11:00:57 · answer #6 · answered by mysstere 5 · 0 0

(4-3)/(5-0) = 1/5

2006-10-06 11:00:32 · answer #7 · answered by Anonymous · 0 0

It's just the rise divided by the run, or 1/5.

2006-10-06 10:55:47 · answer #8 · answered by Sheik Yerbouti 4 · 1 0

m(slope) = (y-y)/(x-x)
so here we have (4-3)/(5-0) or 1/5

2006-10-06 11:04:26 · answer #9 · answered by momogriff 2 · 0 0

slope =(y2-y1)(x2-x1)=(3-4)/(0-5)=-1/(-5)=+0.2

2006-10-06 17:47:27 · answer #10 · answered by yupchagee 7 · 0 0

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