Suppose that a man pushes a 2150 kg car?

Question

from rest to a speed of v, doing 5027 J of work in the process. During this time, the car moves 28.1 m. Ignore friction between the car and the road.

Find the speed v. answer in m/s

Find the horizontal force exerted on the car. answer in N

Answer 1

E = 1/2 mv^2
v^2 = 2E/m
v = sqrt [1/2 (5027 kg m^2/s^2) / (2150 kg)]

solve in m/s


E=Fs
F=E/s
F=(5027 kg m^2/s^2) / (28.1m)

solve in Newtons (kg m/s^2)