How many bushels did the second man pick?

Question

Three men picked 66 bushels of apples. The first man picked 3 times more than the second man and twice as many as the third man. How many bushels did the second man pick?
a. 10, b. 15, c. 24, d. 18

Answer 1

Simplest way of answering this is: Let the number of bushels collected by 2nd man be X. Then 1st man got 3X, and 3rd man 1.5X, as it must be twice smaller than 1st man's quantity. So:
3X+X+1.5X=66
5.5X=66
X=12
Second man got X bushels, meaning he has 12!!

Answer 2

Second man picked x (we don't know how much he picked)

Third man picked y (we don't know how much he picked)

First man picked 3x (he picked 3 times more than the second man)

First man picked 2y (and twice as many as the third man)

So now we have two variable and we need two equations
Since the first guy picked both 3x and 2y those have to be equal
3x=2y

And we know that all together the guys picked 66 bushels
3x + x + y = 66

Now solve the two equations and determine the value for x what the second guy picked.

Hope this helps. Good Luck.

Answer 3

24

Answer 4

d
the second man picks 18 the first then picks 36 and the third 12 which adds up to 66

Answer 5

let x, y, & z be the # of bushels picked by the 1st, 2nd & 3rd men respectively.
x=3y
x=2z
2z=3y
z=1.5y

&

x+y+z=66
3y+y+1.5y=66
5.5y=66
y=12

x=36
z=18
12+36+18=66

D is correct for the 3rd man, none of the answers are correct for the 2nd man