x^4 + x^2 – 12
&
x^2 – 8x + 16
2006-10-06 01:23:40 · 4 answers · asked by olivia b 1 in Education & Reference ➔ Homework Help
Lets take the first eqaution
x^4 + x^2 -12
let x^2 =y
therefore our eq. becomes....
y^2 +y -12
y^2 +(4-3)y-12
y^2 +4y - 3y -12
y(y + 4) -3 (y + 4)
(y-3)(y+4)
now putting back value of X, we get
(x^2 - 3)(x^2 + 4) ANSWER
Again Lets take Equation two
x^2 -8x +16
x^2 - (4+4)x +16
x^2 -4x -4x +16
x ( x - 4 ) -4 ( x - 4 )
( x - 4 ) ( x - 4 ) ANSWER
or (x-4)^2 ANSWER
2006-10-06 03:32:36 · answer #1 · answered by reu_999 2 · 0⤊ 0⤋
x^4 + x^2 - 12 = (x^2 - 3) (x^2 + 4)
x^2 -8x +16 = (x-4)(x-4)
2006-10-06 08:28:15 · answer #2 · answered by Eddie V 2 · 0⤊ 0⤋
F O I L method those are very simple problems
2006-10-06 08:32:44 · answer #3 · answered by reynwater 7 · 0⤊ 0⤋
Please use ADD DETAILS to show what you DO know about this. That way, I can see what you're doing and help you understand how to fix whatever needs to be fixed.
2006-10-06 08:26:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋