Quick qeustion, Im not good in word problems at all...?

Question

If the sides of a square are decreased by 3 cm, the area is decreased by 81 cm2. What were the dimensions of the original square?

Answer 1

solving word problems:
Read the question 3 times. First reading to familiarize yourself with the wording. second reading to understand what is being asked -- usually the last line of the question. Third reading for the variable information or what is given.

dimensions of original square = what is asked
decreased by 3 cm = function you need to use (-3)
now you can write the equasion, let x = the original square....x = (x-3)(x-3) I think

Answer 2

You need two equations here
Let's use s to stand for the original length of the side
The area oof the new square can now be written two ways
(s-3)^2
and
s^2 -81

Since these are equal you can set them equal to each other
(s-3)^2 = s^2 -81
now solve the equation for s
s^2 -6s +9 = s^2 - 81
-6s = -72
s = 12
So the original square was 12 x 12

Answer 3

original size is 15 x 15=225 shrunk 3 is 12 x 12 = 144. 225 -144= 81

Answer 4

the original square was 15x15cm.with an area of 225 sq. cm
decreased by 3, we have 12x12 cm..with an area of 144 sq cm..which is 81 sq cm less than the original square's area:)

Answer 5

enable x = the cost of the motorcycle proprietor in nevertheless air enable w = the cost of the wind against the wind takes 2 hours to bypass 34km. the cost against the wind may be x - w value X Time = Distance (x - w)(2hr)=34km x - w = 17 km/hr the cost with the wind may be x + w value X Time = Distance (x + w)(2hr)=42km x + w = 21 km/hr sparkling up here concurrently x - w = 17 km/hr x + w = 21 km/hr 2x = 38 km/hr x = 19km/hr w = 2km/hr

Answer 6

It appears you can't be spaell or speaking properly at alll