hi, i have a math question. if you have 3x^0y^-2 on top of the equation and 5x^7y^3 on the bottom, how do you simplify? help plz!
2006-10-05 18:45:20 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help
zero times anything is zero then 0*y^-2 =0
then 3x^0 = 1
so the top part is 1
and 5x^7y^3 will stay the same ,, can't think of simple form for it .. maybe the others will help
2006-10-05 18:49:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3X^0 =3*1=3 because X^0 power = 1 anything raised to the equal power = 1
that gives (3*Y^-2)/(5X^7*y^3)
simplify and divide ((3Y^-2)*(Y^-3))/5X^7 which =
(3y^-5)/(5x^7)
written out it becomes 3 times y raised to the minus fifth power divided by 5 times x raised to the seventh power
2006-10-06 02:26:42 · answer #2 · answered by JUAN FRAN$$$ 7 · 0⤊ 0⤋