Write the equation of the line passing through (2, –19) and (–1, –1).?

Question

what do I do? I need help

Answer 1

Hi dear Deb;

Step 1;
well first you need to find the slope Or 'm'
The formula for the slope of the straight line going through the points (x1, y1) and (x 2, y 2) is given by:
m = ( y2 -y1)/ (x2 - x1)
m = (-1 -(-19)) / ( -1 -2) = 18 / (-3) = -6
m = -6;

Step 2;
It is the formula for finding equation of the line
y - y1 = m ( x-x1)
y - (-19) = -6 ( x - 2)
y +19 = -6x +12
y = -6x +12 - 19
y = -6x -7

Good Luck Dear.

Answer 2

To answer this question, you must first determine the slope of the line that passes through these two points. It's important for you to understand that there is only one possible line that can be drawn to connect those two points, so we'll start figuring out what that line looks like by computing the slope.

Slope is "rise over run", meaning we'll look at how much the line goes up from one point to the next, and compare that to how far the line moves from side to side. Or, mathematically:

Y 2 - Y 1
---------------
x 2 - x 2

(-1) - (-19)
-------------- =
(-1) - (2)

18
----- =
-3

= -6

Now - since we know the slope of our line is negative 6, we can determine the equation of the line.

Since the standard equation of a line is y = mx + b, where "m" is the slope of the line, our line has the equation y= -6x + b (we plugged in (-6) for m in the y=mx+b equation).

Let's take one of the points that we know is on the line, how about (-1, -1). Let's plug that in to our equation as we have it so far.

-1 = (-6)(-1) + b

See? All we did was plug in (-1) for y and (-1) for x... now we have

-1 = 6 +b

The only solution to this problem is if b is (-7). Now we have all the info we need - the equation of our line is:

y = -6x - 7

Let's make sure our other point (2, -19) is on this line - plug in 2 for x and -19 for y....

-19 = (-6) (2) - 7 - sure, that's true, so we're looking good - and we have our solution - the line that intersects both (2,-19) and (-1, -1) is y = -6x - 7.

Hope that helped!

Answer 3

you can find the gradient, m, then use the equation y = mx + b, or you can use the equation

(y - y1) / (x - x1) = (y2 - y1) / (x2 - x1)

substitute the points into the equation

(y - -19) / (x - 2) = (-1 - -19) / (-1 - 2)

(y + 19) / (x - 2) = (-1 + 19) / (-1 - 2)

(y + 19) / (x - 2) = 18 / -3

(y + 19) / (x - 2) = -6

multiply both sides by (x - 2)

y + 19 = -6(x - 2)

y + 19 = -6x + 12

subtract 19 from both sides

y = -6x + 12 - 19

y = -6x - 7

Answer 4

Follow this steps :

Since it is only 2 points and our first best assumption is a straightline here. We know that straightline having the form of

y = mx + c

Just substitude your coordinate inside and you will get

-19 = 2m + c ................. (1)]
-1 = -m + c ..................... (2)

Is a simultaneous equation here. Just substitude one another to get the valud for m and c.

In this case; m = -6 c = 5
Put inside the linear equation of y=mx + c and you will get your answer is

y = -6x + 5

Answer 5

y=mx+b
-1=20.-1-+b
-1-=20+
-19=b
y=20x+19

Answer 6

first find gradient of the line.then put y+1 upon x+1.and equal to the gradient you found.

Answer 7

m = -19+1/2+1 = -6

y + 1 = -6(x + 1)

y + 1 = -6x - 6

y = -6x - 7

Answer 8

apply the formula
(x-x1/x1-x2)=(y-y1/y1-y2)
(x1,y1)=(2,-19)
(x2,y2)=(-1,-1)

Answer 9

m= delta(y)/delta(x)

m=-19-(-1))
-------------
2-(-1)

=-18/ 3=-6

y=mx+b

-1=-6*-1+b

b=-7

y= -6 x -7