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5 answers

area of a circle= pi r^2 (pi*radius squared)
area of triangle= 1/2 bh (half*base height)
square= s^4 (side^4)

2006-10-05 16:59:57 · answer #1 · answered by Anonymous · 1 0

area of circle= pi into radius square; area of triangle= 1/2 base into height; area of square= side square

2006-10-06 00:01:33 · answer #2 · answered by Anonymous · 0 0

1.circle:diameter=2 times radius
radius=1/2 the diameter
circumference=2pi*r or pi*d
area=pi*r^2 or pi*d^2/4
area of sector=(central angle/360)pi*r^2 or (1/2)lr where l=length of the arc
length of the arc=(central angle/360)2pi*r
perimeter of the sector=2r+l or d+l

2.triangle:sides opposite to angles A,B and C being a,b and c respectively
area=(1/2)base*height(altitude)
=rt[s(s-a)(s-b)(s-c)] where s is the semi perimeter=(a+b+c)/2
perimeter=a+b+c


3.square:area=side*side or a^2
if the diagonals are given area=(1/2)d1*d2
d=a*rt2 and a=d*rt2/2
perimeter=4a

2006-10-06 00:24:03 · answer #3 · answered by raj 7 · 0 0

what are u a foruth grader so easy. square is w*h and triangle is w*h/by 2.i forgot the circle one.

2006-10-06 00:01:47 · answer #4 · answered by bloo b 3 · 0 0

What formula? Area, perimeter? ??

2006-10-06 00:08:29 · answer #5 · answered by Sheila 3 · 0 0

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