need some help on this one question, I'm stuck!!! Help?

Question

Solve the system by addition or substitution.
3x – 4y = 8
6x – 2y = 10

Answer 1

Solve for x or y in the first equation.

Substitute it in the second equation.

For example, I would solve for x.

3x = 8 + 4y
x = (8 + 4y)/3

Plug that into the second equation to get:

6(8 + 4y)/3 -2y = 10
16 + 8y - 2y = 10
6y = -6
y = -1

Plug that back into both equations (to double-check yourself):
3x - 4(-1) = 8
3x = 4
x = 4/3
6x - 2(-1) = 10
6x = 8
x = 4/3

So, x=4/3, y = -1

Answer 2

1) 3x - 4y = 8

2) 6x - 2y = 10

take eq 1 and solve for y

4y = 3x - 8

y = (3x - 8)/4

plug this into eq 2

6x - 2 [ (3x - 8)/4] = 10

6x - (3x - 8)/2 = 10

multiply by 2 to get rid of the fraction

12x - (3x - 8) = 20

12x - 3x + 8 = 20

9x = 12

x = 4/3 plug this into eq 1

1) 3(4/3) - 4y = 8

4 - 4y = 8

-4y = 4

y = -1


therefore

x = 4/3
y = -1

Answer 3

You mean find x and y in the two equation right? Or you want to add or substract the two equations.

If you want find x and y refer to the answer above. But if you want to add or subract the two equations below is the result.

Sum of the two equations:(3x-4y=8)+(6x-2y=10)
3x+6x-4y-2y=8+10
9x-6y=18

Difference of the two equations: (3x-4y=8)-(6x-2y=10)
3x-6x-4y+2y=8-10
-3x-2y=-2

Answer 4

6x-4y=8
-12x+4y=-20
add to get

-6x=-12
x=2
and now Substitution :
6*(2)-4y=8
12-4y=8
4y=4

y=1

Answer 5

Rev Kev got it right....like they said always remember though to put the answers back into the original equations to check them for accuracy

Answer 6

3x-4y=8

6x-2y=10
3x-y=5
3x-4y=8
subtract
3y=-3
y=-1

3x-4(-1)=8
3x+4=8
3x=4
x=4/3

check
6(4/3)-2(-1)=10
8-(-2)=10
8+2=10

Answer 7

hire a tutor

Answer 8

uhh...i really thought i knew. but now im not so sure. lol.