Can someone please help. I have litterally done everything that I can think of and there is nothing working. The only two symbols you cannot use though are e and Pi. And I was told that you can use one more number. Could the answer be 2^Log base 2 of 5?
2006-10-05 16:12:47 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(.2^(-2))
2006-10-05 16:26:05 · answer #1 · answered by novangelis 7 · 3⤊ 1⤋
(2+2+2+2+2)/2 = 5
2006-10-05 17:06:07 · answer #2 · answered by Mudmutt 2 · 0⤊ 1⤋
2 Ã 2 + 1 = 5
2 + 2 + 1 = 5
2² + 1 = 5
2006-10-05 16:28:17 · answer #3 · answered by Jerry M 3 · 1⤊ 2⤋
I am in Pre_Alg. but what about 2 + 2 + 1 = 5.
I am not that smart but it sounds pretty easy You can also do 2 * 2 + 1 = 5. I hope i helped you if i didn't i'm sorry but i tried. :-)
2006-10-05 16:24:32 · answer #4 · answered by hAnNaH bAnAnA 2 · 1⤊ 2⤋
2^2 +2^0=4+1=5
e^{2ln 2} + e^0=5
and also, you are right:
2^{log_2 5}= 5
2006-10-05 16:53:21 · answer #5 · answered by locuaz 7 · 0⤊ 1⤋
if you can use 2 twice, and use one more #....
2 + 2 + 1
thats 5, right?
2006-10-05 16:21:21 · answer #6 · answered by hellion210 6 · 0⤊ 2⤋