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Let say if player A scores an average of 3 points per game, and he has played a tons of games already.

What fraction of his games will be exactly 3 points/game?

2006-10-05 16:01:37 · 6 answers · asked by gaha 1 in Education & Reference Homework Help

this is the complete question, it might be tough since this is a junior statistics courses problem.

I assume this could be a poisson model but i can't get it to work out.

2006-10-05 16:15:14 · update #1

6 answers

Mike M is right - somewhere between 0 and 1, inclusive. He could get three points per game average by getting three points in every game. He could also get it by getting two points in the first, four points in the second, two points in the third, four points in the fourth, and so on. The question cannot be answered.

2006-10-05 16:07:46 · answer #1 · answered by Anonymous · 0 0

I would guess somewhere near 40...unless "tons" isnt indicitive of thousands...so...assuming "tons" is hundreds..then more like 60..cuz the probability would drop off the more games he/she's played because the chances would seem to me to increase w/ the amount of games played because the odds of playing a 3 point game would become greater...in other words...the more games he/she's played the greater the chancing of running odd numbers like 7 or 2...or even 22...or 0...even in a win like a forfeit..

2006-10-05 23:08:00 · answer #2 · answered by Anonymous · 0 1

How does TONS relate to points?

Had you offered the number or games, you could have created an algebra problem, which might have made more sense,,,even to someone ignorant of algebra.

Re state the Q and let us have another opportunity.

2006-10-05 23:11:20 · answer #3 · answered by DIY Doc 7 · 0 1

it is not possible to tell exactly how many games did he score exactly 3 point....not enough info give...are you sure thats the whole question?

2006-10-05 23:11:39 · answer #4 · answered by jcol 2 · 1 0

3/1000

2006-10-05 23:04:59 · answer #5 · answered by blueone 2 · 0 2

you can't answer this Q with the info given

2006-10-05 23:04:08 · answer #6 · answered by Mike M 1 · 1 0

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