They're both the product of 2 consecutive primes:
15 = 3*5
77 = 7*11
and (3,5,7,11) are consecutive primes.
2006-10-05 15:30:41
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answer #1
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answered by Joe C 3
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77 = 46 + 31
15 = 46 - 31
2006-10-05 15:39:04
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answer #2
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answered by wild_turkey_willie 5
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They both are the fist number in a Ruth-Aaron pair
Seventy-seven is the sum of three squares, 42 + 52 + 62, as well as the sum of the first eight prime numbers.
77 and 78 form a Ruth-Aaron pair under the second definition in which repeated prime factors are counted as often as they occur.
It is possible for a sudoku puzzle to have as many as 77 givens yet lack a unique solution.
Fifteen is a triangular number and a hexagonal number, a pentatope number, and the 4th Bell number. Fifteen is the double factorial of 5. It is a composite number; its proper divisors being 1, 3 and 5. With only two exceptions, all prime quadruplets enclose a multiple of 15, with 15 itself being enclosed by the quadruplet (11, 13, 17, 19). 15 is also the number of supersingular primes.
15 and 16 form a Ruth-Aaron pair under the second definition in which repeated prime factors are counted as often as they occur.
Fifteen is the magic constant of the unique order-3 normal magic square:
15 is the smallest number that can be factorized using Shor's quantum algorithm.
There are 15 solutions to Znám's problem of length 7.
15 is a repdigit in binary (1111). In hexadecimal, as well as all higher bases, fifteen is represented as F.
2006-10-05 15:33:31
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answer #3
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answered by DanE 7
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77 have 4 factors 1,7,11,77
1*77=77
7*11=77
15 have 4 factors 1,3,5,15
1*15=15
3*5=15
The similarity is both has 4 factors
2006-10-05 15:37:33
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answer #4
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answered by safrodin 3
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they are both involved with the figures 46 and 31...both 2 digits
2006-10-06 04:00:01
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answer #5
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answered by sweetfloss8 2
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Both are two-digit numbers. Both are odd.
2006-10-05 15:36:53
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answer #6
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answered by just♪wondering 7
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They are both odd numbers
2006-10-05 15:30:15
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answer #7
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answered by aliciarox 5
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