finding slope of perpendicular line??????

Question

how do i find the slope of a line perpendicular to 2x-5y=3 ???
I know the answer is negative five halfs but can you walk me through the steps on how to get there?? thanks

Answer 1

2x-5y=3
2x=3+5y
2x-3=5y
5y=2x-3
y=(2/5)x-3
SLOPE:2/5
Y-INTERCEPT: -3

Perpendicular line = negative reciprical
negative reciprical of 2/5=
-5/2

Answer 2

First write the original equation in y=mx+b form so you can figure out its slope.

Rewritten, the original equation is

y=(2/5)x-3/5

That means it has a slope of 2/5.

The perpendicular line will have a slope that is the negative reciprocal of the slope of the original line. That is why the slope of the perpendicular line is -5/2, the negative reciprocal of 2/5.

Hope that helps.

Answer 3

the slope of a line is the m in y = mx + b
your equation, the slope is
- 5y = -2x + 3
5y = 2x -3
y = 2/5x - 3/5
the slope is 2/5.
The perpendicular will have the the negative reciprocal slope or -5/2

Answer 4

first, make equation into y=mx+ b form
2x - 5y = 3
-5y= -2x +3
y= 2/5x - 3/5
perpendicular slopes, when u multiply them, the product should be negative 1
so
(x is slope of perpendicular line)
2/5x = -1
x=-5/2
slope of perpendicular is -5/2

Answer 5

Find the slope of the line, by whatever means you prefer. if you get it in the form of y = mx +b, then m is the slope.

The slope of a line perpendicular to this is -1/m by definition.

Hope that helped.

Answer 6

ok first of all you need to get the original equation in terms of y.
So y=2/5x-3/5

Then to find the slope of the line perpendicular find the negative recepricol of 2/5 which is -5/2.

Answer 7

Assuming you can find the slope of the original line (solve for y) perpendicular lines always have opposite reciprocal slopes and parralel lines have the same slope.

Answer 8

you need to find the slope of that line, -a/b, then find the negative reciprocal of that slope. soo... 2/5 if the normal slope, then you flip the fraction and change the sign. -5/2

Answer 9

you have to make it into y=mx+b form so:

2x-5y=3
-5y=-2x+3
y=2/5x-3/5

so the slope is negative recipical which means its exacly the opposite so you flip it around with the opposite sign..so it would be 5/2

Answer 10

if the line is perpendicular it is straight and has no slope. but y=Mx+b where b is your y intercept and m is your slope so

y = 2/5x + 3/5

your slope is 2/5

Answer 11

Solve for Y by moving the three over, and the -5y over. divide by negative 5, then take the negative recipricol of the slope.