Solving equations by using multiplicatin and division: does anyone know the answer to this problem ... -12=2/3z
2006-10-05 15:01:42 · 7 answers · asked by Amber j 1 in Education & Reference ➔ Homework Help
If you had
2z = 4, to get rid of the 2, you would DIVIDE both sides by 2 and you would have
z=2
You do the same thing here.
Since you have 2/3z=-12, divide both sides by 2/3
you get
z=(-12 / 2/3)
when you do that on the calculator, you get
z=-18
2006-10-05 15:02:55 · answer #1 · answered by ĵōē¥ → đ 6 · 1⤊ 0⤋
-12 = 2/3z
Multiply both sides by 3/2 to get rid of the fraction
(3/2) *-12 = z
z = -18
2006-10-05 22:10:34 · answer #2 · answered by JennyAnn 4 · 0⤊ 0⤋
Hm...
Do you mean 2/3 of z? Because 2/3z can be completely different...
2006-10-05 22:09:57 · answer #3 · answered by Bob 4 · 0⤊ 0⤋
-12=2/3z
-3/2*12=2/3z*3/2
-18=z
2006-10-05 22:04:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
yes the answer is -18. to work it out : -12 =2/3z; =(3)*(-12)=2z ; -36=2z; = -36/2 = z; -18=z
2006-10-05 22:07:27 · answer #5 · answered by kiki 1 · 0⤊ 0⤋
I beleive it's -3/-4 or maybe it's 3/4 I haven't done integers in awhile :S
2006-10-05 22:04:08 · answer #6 · answered by Burning out, not fading away 3 · 0⤊ 0⤋
-6, multiply both sides by common denominator, then divide
2006-10-05 22:11:25 · answer #7 · answered by john m 1 · 0⤊ 0⤋