A rod of length L is place in a bowl with radius r, find angle O for equilibrium (the rod make with the horizontal, which is across the mouth of the bowl) . Express answer in term of L and r.
2006-10-05 14:38:55 · 4 answers · asked by Henry T 1 in Science & Mathematics ➔ Physics
I don't understand this question, if one end is set up on the rim of the bowl, and the other end is allowed to fall into the bowl, then the angle is:
O = cos^-1 (L/2r)
That's cos-inverse in there, not one over cos. However, you're not really clear in your wording, so that could be incorrect.
The solution I used involes relating the rod itself, a line drawn from the center of the bowl to the point that the fallen end of the rod touches, and the relation between the horizontal distance covered by these two lines. That should give you three equations, three unknowns.
As soon as you get the horizontal distance covered by the rod in terms of L and r, you can solve for O using the definition of the cosine function.
2006-10-05 14:50:49 · answer #1 · answered by Argon 3 · 0⤊ 0⤋
ZZzzz
2006-10-05 14:55:47 · answer #2 · answered by m c 2 · 0⤊ 0⤋
wow that sucks i have no idea but i just got 2 points
2006-10-05 14:41:50 · answer #3 · answered by psycho 3 · 0⤊ 0⤋
What a question.
2006-10-05 14:40:55 · answer #4 · answered by rzn_880 1 · 0⤊ 0⤋