this one has me stuck with the whole vacuum thing. is it 19.6? or zero? help!
2006-10-05 14:25:24 · 3 answers · asked by <333 3 in Science & Mathematics ➔ Physics
Suppose a rock on Earth is dropped in a vacuum and has an initial speed of 0 m/s. What is the rock's speed after 2 seconds in m/s?? is it 19.6?? or 0?? the vacuum thing has me stuck. help!
2006-10-05 14:27:51 · update #1
Acceleration on earth is taken as 9.8 m/s^2
(9.8m/s^2)*(2s) = 19.6 m/s
Just look at the units if it isn't obvious. Best of luck!
Oh, the deal about the vacuum just tells you to disregard friction with the air, which would be a force who's strength is a function of velocity.
2006-10-05 14:31:17 · answer #1 · answered by Argon 3 · 0⤊ 0⤋
Wake up. The vaccum part is what makes it easier. What that means is you don't have to worry about the rock reaching a terminal velocity because of air friction.
g is 9.8 M/s^2
So the velocity is = Vo + g (time) time in secs
Vo = 0
so its just 9.8 x (time) the time was cut off your question.
2006-10-05 14:29:56 · answer #2 · answered by Roadkill 6 · 0⤊ 1⤋
I believe "vacuum" just means you can ignore air resistance. Do the problem as usual.
2006-10-05 14:30:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋