A migrating elephant herd started moving at the rate of 6 mph. One elephant stood still and was left behind. Then the stray elephant sensed danger and began running at a rate of 10mph to reach the herd. The stray caught up in 5 minutes.
1) how long in hours did the stray run to catch up
2) how far did it run
3) find the distance that the herd traveled while the stray ran to catch up. Then write an expression for the total distance the herd traveled. Let x represent the distance in miles while the elephant stood still
Additional Details
13 minutes ago
My mom and I worked on this for like an hour but could not get the answer. We would like any help we can get on how to solve it! Thanks
2006-10-05 13:43:04 · 2 answers · asked by .margarita. 2 in Science & Mathematics ➔ Mathematics
Wait, your mom worked on this for an hour and couldn't figure it out?
I'm gravely concerned about the future of humanity.
#1: You're given the time - five minutes. This is one twelfth of an hour. (5/60=1/12)
#2: It ran at 10 miles an hour for 1/12 of an hour. Therefore it ran 5/6 of a mile (1/12*10=10/12=5/6)
#3: The herd was moving at 6 mph for 1/12 hours. Therefore it moved 1/2 mile while the stray ran.
#3b: The total distance the herd traveled while the elephant stood still plus the lead it had before the elephant started running is the distance the elephant had to run to catch up. Ergo. 1/2 + x = 5/6, x=1/3 mile.
2006-10-05 13:56:01 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Every 6 minutes the Elephant ran 1 mile. 5 minutes would be about 7/8 ths of a mile or .883 of a mile.you said he caught up in 5 minutes. The heard ran for the same distance the elephant ran to catch up at 6 mph that's a mile every 10 min the heard ran for about 8.33 minutes
2006-10-05 20:55:15 · answer #2 · answered by Anonymous · 0⤊ 1⤋