zero product property?

Question

how do you solve 6x^2+23x+20=0 with the zero product property?

Answer 1

Sorry to say that both the answer you got are wrong:
Remember the composition of a quadratic equation a.x^2 + b.x + c or a.x^2 - b.x + c.
Now remember the quadratic formula for finding the factors/roots
x=(-b±sqrt(b²-4ac))/2a


Once you find the factors you can rearrange as such (x + ?).(x + ?) or (x + ?).(x - ?) = 0
You know one or both terms need to be 0 to make the whole thing zero so find the x that way. The answer should be:
x = -4/3 and x = -5/2

Answer 2

substitute 0 for x and that gives you
6*0^2+23*0+20=0 carry it down and you have
0+0+20=0

20does not equal 0

Answer 3

6x^2+23x+20=0
(x+15)(x+8)
(6x+15)(6x+8)
(3x+5)(3x+4)

x=5
x=4