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when the 7 dwarfs waved goodbye to Snowwhite they walked home in single file Happy was as many places in front of Sleepy as Dopey was behind doc.Sleepy and grumpy were in even numbered places and Dopey was in an odd numbered place.Sneezy was behind Dopey and Doc was behind sleepy but there is no information about Bashfuls place.In what order did the dwarfs walk home.

2006-10-05 10:48:28 · 4 answers · asked by ? 1 in Science & Mathematics Mathematics

4 answers

Bear with me- there's an educational message at the end (and if that doesn't keep you glued to this screen, well then..). Here goes:
To all of you lazy birds out there, the answer is (written first to last):
Happy→Sleepy→Bashful→Doc
→Dopey→Grumpy→Sneezy.
It complies with all the limitations. Here's how I did it:
First, I simplified all the stats (except the even/odd ones, which come later). The guide to this is that the further back in line the dwarf is, the more he will be found on the left side of the equation:
1- Dopey→→Doc=Sleepy→→Happy (numerous arrows go 2 show that those dwarves are not necessarily RIGHT behind each other)
2- Sneezy→Dopey
3- Doc→Sleepy
Looking at these 3 main stats, I can see that a certain few of the dwarves keep popping up, so I decided to make up one BIG, FAT STAT:
Sneezy→Dopey→→Doc
→Sleepy→→Happy
Now look at Dopey. He's the most mentioned dwarf, so let's see:
1) Can only go in 1/3/5/7- odd numbered places.
2) There r at least 3 dwarves in front of him (Doc, Sleepy & Happy), so he can't be 1 or 3
3) There's at least 1 dwarf behind him (Sneezy), so he can't be last in line- 7 ain't possible
4) Dopey goes in 5. How very fitting (he has 5 letters in his name- that could've saved some time...)
From now on it gets a bit easier:
Looking at the first stat
(Dopey→→Doc=Sleepy→→Happy)
& knowing that Dopey's 5th, means that there are only four spaces available for the remaining 3 dwarves in that stat. I also know that Sleepy's in front of Doc, so it must be that the gaps between both pairs are 1. So:
1: Doc goes in 4th, one ahead of Dopey
2: Happy & Sleepy can go either 1 and 2 OR 2 and 3 respectively.
Seeing as I know that Sleepy is in an even numbered spot, I've got to go with 1 and 2.
SHORT RECAP:
7-?; 6-?; 5-Dopey; 4-Doc; 3-?; 2-Sleepy; 1-Happy
Grumpy's even, so he goes in 6th.
BIG, FAT STAT (Sneezy→Dopey→→
Doc→Sleepy→→Happy) says Sneezy has to be behind Dopey, so now that 6th is taken, he comes in last, which leaves dear ol' Bashful a cosy 3rd.
FINAL ORDER:
Sneezy→Grumpy→Dopey→Doc
→Bashful→Sleepy→Happy.
Just goes to show good things happen to HAPPY people ;-)

2006-10-05 12:05:22 · answer #1 · answered by Yankuta118 2 · 0 0

1 Happy
2 Sleepy
3 Doc
4 Dopey
5 Sneezy
6 Grumpy
7 Bashful

The only place left to put Bashful is at the end, since Happy is in front of sleepy the same amount of space as Dopey is behind Doc, and Sleepy is even and Dopey is odd and Doc is behind Sleepy, and Sneezy is behind Dopey, Grumpy has to be even, then Bashful comes last.

2006-10-05 18:12:57 · answer #2 · answered by Anonymous · 0 0

I'll make this an easy suggestion. Map it out on paper with stick figures as the dwarfs. Bashful is the unknown part of the equation that you are suppose to figure out. You need to do this homework yourself to learn how to find this missing value(Bashful) or you won't be learning anything.

2006-10-05 17:54:09 · answer #3 · answered by Pundit Bandit 5 · 0 0

in just the order mentioned above :-)

2006-10-05 17:50:49 · answer #4 · answered by egyptsprincess07 3 · 0 0

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