If you can you will get ten points
(I am being for real)
2006-10-05 10:26:17 · 4 answers · asked by mr.jeremy 2 in Science & Mathematics ➔ Mathematics
for first answer, that isnt proof
2006-10-05 10:29:06 · update #1
we know that(frrom 1st link)
.999999... = 1(correct)
from the second link
1=2 (falacious)
because a= b and b= c => a =c so from above
,9999..... = 2
2006-10-06 05:32:19 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 2⤋
Hi. .999... is not =2. It's equal to 1.
I'll prove it 2 ways, first algebraically.
let N = .999...
multiply both sides by 10 and you get 10N = 9.99...
now subtract:
10N = 9.999....
-N = .999...
9N = 9 Now, divide both sides by 9 and you get N=1.
We started by saying N=.999... and performed legal moves and ended up with N=1, therefore .999... = 1.
My second way is a little more fun. Try subtracting .999... from 1.
1.000...
-.999...
(You need to cross out the 1 and put a 9 and so on.)
Since the result is 0, the numbers must be equal.
2006-10-05 17:27:25 · answer #2 · answered by Melody 3 · 0⤊ 1⤋
well when you have a repeating number you put that number over nine. so like with .999 9/9 =1 1.9999 repeating equals 2 .33333 repeating = 1/3
2006-10-05 17:30:10 · answer #3 · answered by Kev32189 3 · 0⤊ 2⤋
I need a little more info. Your question is a little vague.
2006-10-05 17:28:26 · answer #4 · answered by FlashGordon 3 · 0⤊ 1⤋