if each side of a square is increased by 50%, what is the percent of increase in the area of the square?

Answer 1

125%

If a square has side x, it's area is x^2.
If you increase each side by 50%, each side would measure 1.5x. The area of this square is 2.25 x^2, which is 125% more than 1x^2.

Answer 2

a 2 x 2 square has an area of 4
increasing the sides by 50 % gives
a 3 x 3 square has an area of 9
which is 9 /4 or 225% bigger

lets see how it works with
a 4 x 4 square has an area of 16
increasing the sides by 50% gives
a 6 x 6 square has an area of 36
which is 36 / 16 or 225% bigger

Answer 3

Work this out a square of 10cm x10cm = 100cm squared.
50% of 10 = 5 so add 5cm to the 10 cm you already have
what does a square of 15 cm x 15 cm =???
I'm not going to do everything for you.
Good luck

Answer 4

If earlier side was X (and hence area was X^2), the length of the side after the increase is 1.5 X.
Hence the area is (1.5X) x (1.5X) = 2.25 X^2
Increase of area = (2.25 - 1.0) X^2 = 1.25 X^2
Percentage increase = (1.25/1 x 100)% = 125%

Answer 5

letthe original side be x
original area=x^2
revised length=3/2x
revised area=9/4x^2
%age increase in area=(9/4)x^2-x^2 /x^2 *100=125%

Answer 6

Area is length square so:
original square A=s^2
new square A=(1.5s)^2=2.25s^2

the new square is (2.25s2-s^2)/s^2=1.25=125%

Answer 7

Hi. 225%.