find the number of square units in the area of a square if the length of the diagonals are each 18.?

Answer 1

Let X=Side of the square
Let A=Square Area

A = X^2

Use Pythagrian's Theorem
X^2+X^2 = 18^2
2X^2 = 324
X^2 = 162
X = +√162 or -√162
Since length must be positive
X=√162

A = X^2 = (√162)^2 = 162
Therefore the area of the square is 162 square units

Answer 2

use the pythagorean theorem a squared + b squared + c squared where c is the hypotenuese of a right triangle. In this example c = 18 because it is a square. So 18 squared =324.

So a squared + b squared must = 324 divide 324 in half because both sides of the right triangle have to be equal, since it is a square. 324/2 = 162 the square root of 162 = 12.727
so if you multiply length x width in this example you multiply
12.727 x 12.727 and you get the same 162. OR
The area of a square is the length of the diagonal squared divided by 2

So the area of a square with a diagonal of 18 = 162.

Answer 3

Diagonals are 18, so diagonal squared is 324.

The diagonal is a hypotenuse of a right triangle, so using the Pythagorean theorem, each side must be the square root of (324/2), or sqrt(162). Multiply the two diagonals to get the area:

A = 162

Answer 4

area of a rhombus or square given the diagonals is 1/2d1d2
so the area=1/2*18^2=162 square units
aliter
by using the pythagoras theorem
2s^2=18^2
s^2=18^2/2=162 sq.units

Answer 5

Using the pythagorean theorem, x^2+x^2=18^2
2x^2=324
x^2=162

The area of the square is x^2, or 162 square units

Answer 6

4) The volume 15 will be written because the sum of two or 3 consecutive integers. what's the sensible large difference between the made from the set of two numbers and the made from the set of three numbers? for 3 numbers) the numbers are 4, 5 and six, (integer skill total volume, and four+5+6 = 15) , hence the product = 4x5x6= one hundred twenty (produce skill multiply) for 2 numbers) they are 7 and eight, the positve large difference = 8-7 = a million (large difference skill subtract... to get an excellent volume.... do: the biggest volume - the smallest volume) 8) evaluate: 2+ 4(3)-5, utilizing BODMAS, brackets, (of) branch, multiplication, addition and subtraction, grants the order of the fashion to attempt this question, start up with the brackets, then any divietcn, multiplication... ect to 4x3 = 12, so 2+12-5 = properly, 2+12 = 14, then -5, =9 wish this helps

Answer 7

If the diagonal is 18, each side measures 18/sqrt2.
Area = (18/sqrt2) squared, which is 162

Answer 8

The sides are found by using the Pythagorean theorem.
x^2 + x^2 = 18^2
2x^2 = 324
Divide both sides by 2
x^2 = 162
x = sqrt(162)
The area is sqrt(162) times sqrt(162) = 162

Answer 9

a^2 + b^2 = c^2
a = b

a^2 + a^2 = c^2
2a^2 = c^2
2a^2 = 18^2
2a^2 = 324
a^2 = 162
a = sqrt(162)

A = a^2
A = (sqrt(162))^2
A = 162

ANS : 162 square units

Answer 10

162, I think. I might have forgotten my 45-45 right triangles.