math homework help plzz!?

Question

(x^3y^3)^4 (xy^4)^-3 / x^3y^4


HELP!

Answer 1

There are 3 rules here:

1) Anything to a minus power is the same as the inverse (1/x) to the same positive power. --- x^-2 = 1/x^2 (and the same holds true the other way round, of course - dividing by something changes the sign of the power)

2) When raising something to a power twice (as in the first and second brackets, one multiplies the powers --- (x^3)^4 = x^12

3) When multiplying two instances of the same variable which have different powers, one adds the powers --- x^2 times x^3 = x^5

You just simplify your expression using these rules to give a term in x^n * y^m

First remove the brackets and the division sign (Rules 1 & 2):

x^12 * y^12 * x^-3 * y^-12 * x^-3 * y^-4

group the terms in x and y and add the powers (Rule 3):

x^(12-3-3) * y(12-12-4)

result:

x^6 * y^-4 (or x^6/y^4, if you prefer)

Answer 2

(x^3y^3)^4 (xy^4)^-3 / x^3y^4


* means multiplication

okay, (X^Y)^Z = X ^ (Y*Z)

So we now have

x^12 * y^12 * (xy)^-12 / (x^3 * y^4)

Now, Because (X*Y)^Z = X^Z * Y^Z,

x^12 * y^12 * x^-12 * y^-12 / (x^3 * y^4)

THen, Because X^A * X ^-A = 1,

1/ (x^3 * y^4)

Answer 3

a million. 25% of what's 28 25%= 0.25 of X (as in multiplication, aka cases) what=X (as in variable) is= =(equivalent sign) so, 25% (0.25) of (cases) what (X) is (=) 28 .25 cases X=28 .25x=28...divide .25 on the two aspects to isolate x x=112

Answer 4

There are 3 rules you may want to consider when solving this problem:
1.) x^a * x^b = x^(a+b)
2.) x^-a = 1/x^a
3.) (x^a)^b = x^(ab)

If you can apply these rules correctly to your problem, you should able to solve it.

Answer 5

go to www.ohiocountypubliclibrary.org and go on there they have a sit called homeworkhelp were u can get a real online tutor try it out helps me alot

Answer 6

(x^4y^12) x (xy^12)

Answer 7

try a calculator