the city requires a linear decline of 2.25% for all waste line traveling to the sewer. a house that is 45 foot above the sewer, how long of pipe is needed to run to the sewer to be in code?
2006-10-05 09:22:08 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A linear decline of 2.25% is equivalent of a line with slope -9/400
Let 45 feet = height of a right triangle
Let L be the Length of pipe = hyp of right triangle
Let B = base of right triangle
B = 45*400/9 = 2000 ft
Use pythagrians therem:
45^2 + 2000^2 = L^2
L = √4002025 = 2000.506 ft
Therefore the length of the pipe is approx 2000.5 ft
2006-10-05 09:59:01 · answer #1 · answered by Mariko 4 · 0⤊ 0⤋
The plan view of the pipe should be 45/.0225 = 2000 ft.
Are you sure the 2.25% isn't a minimum value? A 45' drop is probably a lot more than average for a short run, unless you are nearly half a mile from the sewer line.
2006-10-05 16:31:03 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
The decline of 2.25% means that vertical elevation drops 2.25 ft for every 100ft of horizontal distance. You need a decline of 45ft; therefore the horizontal distance must be 100*45/2.25. The lenght of pipe is the hypotenuse of a triangle with the vertical distance as one leg, and the horizontal distance the other. The length is then sqrt[45^2 + (100*45/2.5)^2].
2006-10-05 16:27:15 · answer #3 · answered by gp4rts 7 · 1⤊ 0⤋
Approx. 1185 foot.
2006-10-05 16:41:26 · answer #4 · answered by alam_1209 1 · 0⤊ 0⤋
this is not a rise over run question. the formula for rise over run is M= y2-y1 over x2-x1. if you are using this formula you have to get the points first and fit them into the formula.
2006-10-05 16:48:07 · answer #5 · answered by mixedlinda 1 · 0⤊ 0⤋
YES
2006-10-05 16:25:08 · answer #6 · answered by peicer u 2 · 0⤊ 2⤋