If it takes 4 N to push horizontally on your book to make it slide at a constant velocity, how much force of friction acts on the book?
2006-10-05 09:06:04 · 4 answers · asked by paul_da_pimp90 1 in Science & Mathematics ➔ Physics
As the net froce actiong on system is zero coz its moving with constant velocity.Friction cant be zero.
Therefore the force of friction(f) will be
f=(cofficeint of friction)*(normal reaction)
and force of friction (f) < the horizontal force applied.it cant be equal.
2006-10-05 09:17:20 · answer #1 · answered by Amarbir Singh 2 · 0⤊ 1⤋
Friction is a force exerted at right angles to the weight of the book. If the book is on a horizontal surface, then the force of friction is also horizontal. For the book to move at constant velocity (f=ma, a=0), there must be no net force acting on it. Therefore, the frictional force must exactly equal the horizontal push force.
2006-10-05 16:11:53 · answer #2 · answered by gp4rts 7 · 2⤊ 0⤋
You are pushing your book with a 4N horiztonal force. Your book is moving at a constant velocity. This would mean that there is no acceleration, therefore, net force acting on the book is zero.
Since you are putting a 4N force on the book, thier must also be a 4N force opposing the force you are placing on the book to get a net force equal to zero. This net force in the direction opposite the direction of motion is called friction. In this case, the frictional force is EXACTLY equal to the force you are placing on the book in order to get a net force of zero, no accleration, and a constant velocity.
2006-10-05 16:37:31 · answer #3 · answered by msi_cord 7 · 0⤊ 0⤋
http://en.wikipedia.org/wiki/Friction
2006-10-08 20:37:08 · answer #4 · answered by Surya M. 3 · 0⤊ 0⤋