2006-10-05 08:12:19 · 7 answers · asked by troy w 1 in Education & Reference ➔ Higher Education (University +)
so, what you need to do is subtract the 1/a and put it on the other side
so, you have:
1/b = c-1/a
now multiply by b for both sides so you get
b(c-1/a)=1
now divide by (c-1/a)
so you get b=1/(c-1/a)
2006-10-05 08:14:55 · answer #1 · answered by confused1832 2 · 0⤊ 1⤋
Due to lack of information and values it is not possible to calculate a numeric value for b. However as an eqation you would do it as follows.
1/a + 1/b = c
so 1/b = c - 1/a
so using substitution
1/(c - 1/a) = b
2006-10-05 15:15:04 · answer #2 · answered by quatt47 7 · 0⤊ 1⤋
1/a + 1/b = c
a + a/b = ca
ab + ab = cab
1 + 1 = c
2 = c
Seems odd to me
2006-10-05 15:16:08 · answer #3 · answered by Anonymous · 0⤊ 1⤋
IF we solved it,you wouldn't learn anything
2006-10-05 15:14:17 · answer #4 · answered by Anonymous · 1⤊ 0⤋
1/a + 1/b = c
1/b = c - 1/a
b(1/b) = (c - 1/a)b
1/(c - 1/a) = b
2006-10-05 15:16:56 · answer #5 · answered by DexterLoxley 3 · 0⤊ 1⤋
b=b smart enough to figure it out on your own
2006-10-05 15:14:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
???
2006-10-05 15:14:14 · answer #7 · answered by victor y 3 · 0⤊ 1⤋