3x – 4y = 8
(-2)(6x – 2y) = (-2)10
3x – 4y = 8
-12x + 4y = -20
Add the two equations and you get:
-9x = -12
x=12/9 = 4/3
Solve for y:
3x – 4y = 8, -4y=8-3x
y=(8-3x)/-4
Substitute 4/3 for x
y=(8-3(4/3))/-4 = -1
Therefor:
x=4/3
y=-1
2006-10-05 07:56:59
·
answer #1
·
answered by Mariko 4
·
0⤊
0⤋
Solve by addition. Multiply one or both equations by some number (not necessarily the same number for both equations) so that the co-efficients of x, or those of y, are opposites. For example, in this one system I found online,[1]
x - 2y = 14
x + 3y = 9
just invert the first (or second, but I'll do the first) equation to read
-x + 2y = -14
x + 3y = 9.
Add:
5y = -5 (the x's went away); so y = -1.
Thus, since x - 2y = 14, then x - 2(-1) = 14, or x+2 = 14, so x=12.
(If it's easier on you, just subtract one from the other.)
Alternatively, triple the first equation and double the second, to read
3x - 6y = 42
2x + 6y = 18,
to get rid of the y's. Now add, and get 5x = 60, so that x = 12. And x - 2y = 14, so 12 - 2y = 14. Solve for y and get that y = -1.
If you prefer, solve by substitution. Solve one equation for x (or y) and get something like, x = 11y + 1/7, or whatever. Substitute this for x in the other equation, and solve that for y. Now you know y. Get x the same way as above, substituting the value of y into either equation and solving.
Hope that helps,
2006-10-05 08:20:25
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
1) x =4 y=1
2) x=2 Y=1
2006-10-05 08:01:00
·
answer #3
·
answered by Maral 2
·
0⤊
0⤋
3x - 4y = 8 - - - - - - - Equation 1
6x - 2y = 10 - - - - - - Equation 2
- - - - - - - - - - -- - - - - - - -
Multiply -2 for equation 2
-2(6x) - (-2)(2y) = -2(10)
-12 + 4y = - 20
new equation 2
- - - - - - - - - - - - - - - - - - - - - -
3x - 4y = 8
-12x + 4y = - 20
- - - - - - - - - - -
- 9x + 0 = - 12
- 9x = - 12
- 9x/- 9 = -12/- 9
x = 4/3
The answer is x = 4/3
The solution ser is { 4/3 }
Insert the x value into the equation 1
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
Solving for y equation 1
3x - 4y = 8
3(4/3) - 4y = 8
12/3 - 4y = 8
4 - 4y = 8
4 - 4y - 4 = 8 - 4
- 4y = 4
- 4y/-4 = 4/- 4
y = - 1
The answer is y = -1
The solution set is { - 1 }
Insert the y value into equation 1
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
Check for equation 1
3x - 4y = 8
3(4/3) - 4(- 1) = 8
12/3 + 4 = 8
4 + 4 = 8
8 = 8
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
Check fkor equation 2
6x - 2y = 10
6(4/3) - 2(- 1) = 10
24/3 + 2 = 10
8 + 2 = 10
10 = 10
- - - - - - - - - - - - - - - - - - - -
The solution set is { 4/3, -1 }
2006-10-05 09:33:26
·
answer #4
·
answered by SAMUEL D 7
·
0⤊
0⤋
well, you could do it this way:
you multiply the top equation by 2 so that it becomes 6x - 8y = 16. then you multiply the bottom equation by -4 so that it becomes -24x + 8y = -20. Then the -8y and +8y cancel out, so that the equations become 6x = 16 and -24 = -20. solve one of the equations for x, and substitute that x value in the other equation, and you get y. you now have your x and y value.
after doing that, your answer will be (4/3, -1).
hope this helps :-)
2006-10-05 08:06:33
·
answer #5
·
answered by ♥heartbroken♥ 3
·
0⤊
0⤋
You must choose to either eliminate one variable by getting both coefficients the same and subtracting, or getting the coefficients to be opposites of each other and adding. I always prefer to add...less chance to make errors.
I will choose to multiply the first equation by -2, then add
-6x+8y=-16
6x-2y=10
6y=-6
y=-1
now put -1 in for y in either equation and solve for x
3x -4(-1)=8
3x+4=8
3x=4
x=4/3
Check both in the other equation.
2006-10-05 09:57:59
·
answer #6
·
answered by mom 7
·
0⤊
0⤋
3x - 4y = 8
6x - 2y = 10
6x - 2y = 10
-2y = -6x + 10
y = 3x - 5
3x - 4(3x - 5) = 8
3x - 12x + 20 = 8
-9x + 20 = 8
-9x = -12
x = (4/3)
y = 3(4/3) - 5
y = 4 - 5
y = -1
ANS : ((4/3),-1)
2006-10-05 12:36:18
·
answer #7
·
answered by Sherman81 6
·
0⤊
0⤋
3x-4y=8-----(1)
6x-2y=10-----(2)
multiply eqn (1) by 2 and multiply eqn (2) by 4
we get
6x-8y=16
24x-8y=40
now subtract these two eqns
we get
6x-8y-24x+8y=16-40
-18x=-24
x=4/3=1.333
now put value of x in either eqn (1) or (2) to calculate value of y
using in eqn(1)
3(4/3)-4y=8
4-4y=8
4y=-4
y=-1
hence x=4/3, y=-1
2006-10-05 08:06:40
·
answer #8
·
answered by Amarbir Singh 2
·
0⤊
0⤋
You replace "y" for "x+a million" in the equation 4x-3y=0. a million). 4x - 3(x+a million) = 0 then you particularly distribute. 2). 4x - 3x - 3 = 0 upload the 4x and -3x. 3). x - 3 = 0 Use the addition property of equality. 4). x = 3 replace "x" in the equation y = x+a million to discover "y" 5). y = 3+a million upload. 6). y = 4
2016-10-18 21:13:42
·
answer #9
·
answered by ? 4
·
0⤊
0⤋
-2* [3x – 4y ]= -2* [8 ] then :
-6x+8y = -16
6x – 2y = 10
add them :
6y = -6 so y= -1
then :
6x – 2y = 10 -->> y= -1 -- >> 6x + 2 = 10 so 6x=8 -->> x = 8/6
that`s it ;-)
2006-10-05 08:03:10
·
answer #10
·
answered by Mahsa hamishe Irani 2
·
0⤊
0⤋