2006-10-05 07:22:52 · 15 answers · asked by brandywine614 1 in Science & Mathematics ➔ Mathematics
when they say evaluate, they just want you to plug in the values they give you and solve:
3a – 4b
3(4) - 4(-4) ----> negative multiplied by negative = positive
12 + 16
=28
2006-10-05 07:34:15 · answer #1 · answered by Anonymous · 1⤊ 0⤋
12+16 = 28
2006-10-05 14:25:01 · answer #2 · answered by Andrew H 1 · 1⤊ 0⤋
3a - 4 b = 3*4 -(4*-4) = 12 - (-16) = 12 + 16 = 28
explaination = negative of a negative is a positive
2006-10-05 14:25:43 · answer #3 · answered by cuteniceprty 2 · 1⤊ 0⤋
3a-4b=3*4-4(-4)=12+16=28
2006-10-05 14:24:51 · answer #4 · answered by yupchagee 7 · 1⤊ 0⤋
3a-4b substitute a for 4 and b for -4
3(4)-4(-4)
12+16
28
2006-10-05 17:17:13 · answer #5 · answered by Brandi S 1 · 1⤊ 0⤋
=3a-4b
=3(4)-4(-4)
=12+16
=28
2006-10-05 14:25:27 · answer #6 · answered by Eshwar 5 · 0⤊ 0⤋
3a-4b=
3(4)-4(-4)=
12+16 when multiplying two negatives, they become positive.
Therefore, your answer is 28
2006-10-05 14:45:20 · answer #7 · answered by drea_1078 2 · 1⤊ 0⤋
+28
(3a – 4b,
GIVEN: a=4,b=-4
Let us put these values in 3a-4b
i.e.
3*(4)-4(-4)
=12+16
=28)
2006-10-05 14:54:56 · answer #8 · answered by Anonymous · 1⤊ 0⤋
3 times 4 is 12. so 3(4)=12
4 times -4 is -1 so 4(-4)=-16
12-(-16)=12+16=28
2006-10-05 14:25:45 · answer #9 · answered by john 3 · 1⤊ 1⤋
20
2006-10-05 14:25:46 · answer #10 · answered by Anonymous · 0⤊ 3⤋